Question

我有一个问题。我有两个员工和工资表，我想显示所有员工的全名和工资等级，其grade_ID是2或3，按employee_ID排序。

以下是表格：

Salary_ID      LOW_SALARY       High Salary
1                1              250000
2                250001         500000
3                500001         750000
4                750001         999999

EMPLOYEE_ID     FIRST_NAME     Last_NAME   Salary
1               James          Smith       800000
22               Roy           Red         375000
2                Ron           Johnson     550000
5                Rob           Green       225000

我知道我必须加入这些表，这是我到目前为止所做的：

QUERY

SELECT employees2.FIRST_NAME,
       employees2.last_name,
       salary_grades.SALARY_GRADE_ID,
       employees2.SALARY
FROM employees2,
     salary_grades
ORDER BY employees2.EMPLOYEE_ID;

接下来我该怎么办？我被卡住了。谁能帮我吗？谢谢。

Answer 1

这可能是您正在寻找的查询：

SELECT E.EMPLOYEE_ID
    ,E.FIRST_NAME
    ,E.LAST_NAME
    ,E.SALARY
FROM employees E
INNER JOIN salary S ON S.LOW_SALARY <= E.SALARY
                      AND S.HIGH_SALARY >= E.SALARY
                      AND S.SALARY_ID IN (2,3)
ORDER BY E.EMPLOYEE_ID

希望这会对你有所帮助。

Answer 2

只需使用一个连接条件，将雇员工资与工资等级的上限和下限进行比较，即

SELECT E.*, S.* FROM Employee AS E
INNER JOIN dbo.Salary AS S 
ON S.LOW_SALARY <= E.Salary AND S.High_Salary >= E.Salary

如果需要，您可以按Salary_Id在2到3之间进行过滤

注意：此语法应适用于3种类型的服务器。

测试数据，对于SQL Server：

CREATE TABLE Salary (Salary_Id INT, LOW_SALARY INT, High_Salary INT)
INSERT INTO Salary VALUES(1,1,250000)
INSERT INTO Salary VALUES(2,250001,500000)
INSERT INTO Salary VALUES(3,500001,750000)
INSERT INTO Salary VALUES(4,750001,999999)

CREATE TABLE Employee (Employee_Id INT, FIRST_NAME varchar(50), Last_NAME varchar(50), Salary INT)
INSERT INTO Employee VALUES(1, 'James', 'Smith', 800000)

Answer 3

我将给出SQL Server（2008+）答案。

SELECT E.FIRST_NAME, E.last_name, S.SALARY_GRADE_ID, E.SALARY
FROM employees2 E
JOIN salary_grades S  ON (E.SALARY BETWEEN S.LOW_SALARY AND S.HIGH_SALARY) AND S.SALARY_ID IN (2, 3)
ORDER BY  E.EMPLOYEE_ID;

Answer 4

SELECT employees2.FIRST_NAME, employees2.LAST_NAME, employees2.SALARY, salary_grades.SALARY_GRADE_ID
FROM  employees2, salary_grades
WHERE employees2.SALARY BETWEEN salary_grades.LOW_SALARY AND salary_grades.HIGH_SALARY 
ORDER BY salary_grades.SALARY_GRADE_ID

所以我尝试使用这个脚本，它可以工作，但我使用IN在sqldeveloper中显示2和3的范围？

加入两个表SQL

QUERY

4 个答案: