这是我想要实现的目标：
我的帖子属于A，B，C，D类。我想要显示A类中包含的帖子，但我不想显示C类中包含的帖子。所以，如果我运行查询，我希望此帖子在A，B，C，D中不显示，因为它也属于C类。我怎么做到这一点？
$notInCategories = array(103,106,132,102,10,57,58,28,48);
$args = array(
'post_type' => 'post',
'post_status' => 'publish',
'order_by' => 'ID',
'tax_query' => array(
'relation' => 'AND',
array(
'taxonomy' => 'category',
'field' => 'id',
'terms' => array('10','11','12')
),
array(
'taxonomy' => 'category',
'field' => 'id',
'terms' => $notInCategories,
'operator' => 'NOT IN',
),
),
'meta_query' => array(
'relation' => 'AND',
array(
'key' => 'joke_type',
'value' => $type,
'type' => 'CHAR',
'compare' => '='
),
array(
'key' => 'joke_rating',
'value' => 3,
'type' => 'SIGNED',
'compare' => '>='
)
)
);
$myquery = new WP_Query( $args );
echo '<p>REQUEST:'.$myquery->request.'</p>';
这是打印的内容：
REQUEST:SELECT SQL_CALC_FOUND_ROWS wp_njkf_posts.ID FROM wp_njkf_posts
INNER JOIN wp_njkf_term_relationships ON (wp_njkf_posts.ID = wp_njkf_term_relationships.object_id)
INNER JOIN wp_njkf_postmeta ON ( wp_njkf_posts.ID = wp_njkf_postmeta.post_id )
INNER JOIN wp_njkf_postmeta AS mt1 ON ( wp_njkf_posts.ID = mt1.post_id )
WHERE 1=1 AND ( wp_njkf_term_relationships.term_taxonomy_id IN (11,12,13)
AND wp_njkf_posts.ID NOT IN ( SELECT object_id FROM wp_njkf_term_relationships
WHERE term_taxonomy_id IN (11,30,50,59,60,104,105,108,134) ) )
AND wp_njkf_posts.post_type = 'post'
AND ((wp_njkf_posts.post_status = 'publish'))
AND ( ( wp_njkf_postmeta.meta_key = 'joke_type'
AND CAST(wp_njkf_postmeta.meta_value AS CHAR) = 'joke' )
AND ( mt1.meta_key = 'joke_rating' AND CAST(mt1.meta_value AS SIGNED) >= '3' ) )
GROUP BY wp_njkf_posts.ID
ORDER BY wp_njkf_posts.post_date
DESC LIMIT 0, 10
LATER EDIT：我现在明白为什么它为term_taxonomy_id打印的方式不同。这是因为term_taxonomy_id与类别ID不同。 term_taxonomy_id是类别id（表term_taxonomy中的term_id）和post（term_relationship中的object_id）之间的连接 - 我不明白它为什么不排除那些类别..
答案 0 :(得分：0)
尝试在php文件中使用以下代码。
$args = array(
'post_type' => 'post',
'posts_per_page'=> your_desired_number_of_post,
'tax_query' => array(
'relation' => 'AND',
array(
'taxonomy' => 'category',
'field' => 'slug',
'terms' => array( 'your_category_here' ),
),
array(
'taxonomy' => 'category',
'field' => 'slug',
'terms' => array( 'your_category_to_exclude_here' ),
'operator' => 'NOT IN',
),
),
);
$query = new WP_Query( $args );
我希望有所帮助，
MMK。
答案 1 :(得分：0)
您可以使用group by和having执行所需操作。将复杂的查询与简单的问题联系起来有点困难。但是，假设带有id列表的表是wp_njkf_term_relationships，那么你需要类似的东西：
select tr.object_id
from wp_njkf_term_relationships tr
group by tr.object_id
having sum(tr.term_taxonomy_id in (139, 133, 45, 135) ) > 0 and
sum(tr.term_taxonomy_id in (103, 106, 132, 102, 10, 57, 58, 28, 48) ) = 0;
我建议您一次添加一个表的其余逻辑。
答案 2 :(得分：0)
您如何看待使用子查询：
SELECT * FROM (SELECT * FROM table WHERE category IN ('A') ) AS posts_category_a WHERE category NOT IN ('C')
答案 3 :(得分：0)
$args = array(
'post_type' => 'post',
'posts_per_page'=> 100,
'tax_query' => array(
'relation' => 'AND',
array(
'taxonomy' => 'category',
'field' => 'slug',
'terms' => array( 'CAT 1' ),
),
array(
'taxonomy' => 'category',
'field' => 'slug',
'terms' => array( 'CAT 2','CAT 3', 'CAT 4' ),
'operator' => 'NOT IN',
),
),
);
我有4个帖子：post1，post1.1，post2和post3
所有帖子都在CAT 1，CAT 2和CAT 3类别中。
post1.1仅属于CAT 1类。
当我运行代码时，结果只包含一个帖子，该帖子是post1.1。
我希望这会对你有所帮助。
答案 4 :(得分：0)
当我必须检查它们不属于这些特定类别时，我最终使用了这个：
$args = array(
'orderby' =>'rand',
'post_type' => 'post',
'post_status' => 'publish',
'posts_per_page' => 10,
'order_by' => 'ID',
'category__not_in' => $notInCategories,
'meta_query' => array(
'relation' => 'AND',
array(
'key' => 'joke_type',
'value' => $type,
'type' => 'CHAR',
'compare' => '='
),
array(
'key' => 'joke_rating',
'value' => 3,
'type' => 'SIGNED',
'compare' => '>='
)
),
'fields' => 'ids'
);
这是因为他们需要处于特定类别时：
$args = array(
'orderby' =>'rand',
'post_type' => 'post',
'post_status' => 'publish',
'posts_per_page' => 10,
'order_by' => 'ID',
'category__in' => $categories,
'meta_query' => array(
'relation' => 'AND',
array(
'key' => 'joke_type',
'value' => $type,
'type' => 'CHAR',
'compare' => '='
),
array(
'key' => 'joke_rating',
'value' => 3,
'type' => 'SIGNED',
'compare' => '>='
)
),
'fields' => 'ids'
);
它有更多的代码，但最后还有一个如果做了诀窍......我本来想理解为什么我以前的尝试没有用，但我想这仍然存在于Wordpress的奥秘中。 / p>