Question

我正在使用Codeigniter。我想用各自的类别显示所有帖子。我已经制作了一个代码，但它只显示了一个帖子类别。为什么我的代码没有得到帖子的所有类别？任何解决方案或改进都会很好。这是我的代码：

$this->db->select("posts.*, categories.*");
$this->db->from( 'posts' );

//get cats
$this->db->join('post_cat', 'posts.post_id = post_cat.post_id', 'LEFT');
$this->db->join('categories', 'post_cat.cat_id = post_cat.cat_id', 'LEFT');

//get published blogs
$this->db->where('post_type', 'blog');
$this->db->where('post_status', 'published');

$this->db->group_by("posts.post_id");
$this->db->order_by("post_id", "desc");

$query = $this->db->get();

return $query->result_array();

Answer 1

我猜你在这里做了拼写错误。

请尝试以下代码：

$this->db->select("posts.*, categories.*");
$this->db->from( 'posts' );

//get cats
$this->db->join('post_cat', 'posts.post_id = post_cat.post_id', 'LEFT');
$this->db->join('categories', 'post_cat.cat_id = categories.id', 'LEFT');
// you did typo in above statement here ==> post_cat.cat_id = post_cat.cat_id

//get published blogs
$this->db->where('post_type', 'blog');
$this->db->where('post_status', 'published');

$this->db->group_by("posts.post_id");
$this->db->order_by("post_id", "desc");

$query = $this->db->get();

return $query->result_array();

Answer 2

我找到了解决方案，现在是：

//select posts,cats,tags
$this->db->select("posts.*, GROUP_CONCAT(DISTINCT categories.cat_slug,'-',categories.cat_name) as cat",FALSE);
$this->db->from('posts');

//join cats
$this->db->join('post_cat', 'post_cat.post_id = posts.post_id', 'LEFT');
$this->db->join('categories', 'categories.cat_id = post_cat.cat_id', 'LEFT');

//get published blog
$this->db->where('post_type', 'blog');
$this->db->where('post_status', 'published');

$this->db->group_by("posts.post_id");
$this->db->order_by("post_id", "desc");

$query = $this->db->get();

return $query->result_array();

获取所有类别的帖子

2 个答案: