Question

当我运行程序时，我会输入正确的答案，但它总是标记为错误：

（10，'+'，2）
  12个
  ...
  错误的答案，答案是12！

以下是错误的代码部分：

Player_answer = input()
print ("...")
time.sleep (0.5)

if operation==("+"): #check answer
    answer = num1+num2  #This works out the real answer

    if Player_answer == answer:  #This works out if the player is correct
        print("That's the correct answer")
        score = score + 1
    else:
        print("Wrong answer, the answer was",answer,"!")

if operation==("*"):
    answer = num1*num2

    if Player_answer == answer:
        print("That's the correct answer")
        score = score + 1
    else:
        print("Wrong answer, the answer was",answer,"!")

elif operation==("-"):
    answer = num1-num2

    if Player_answer == answer:
        print("That's the correct answer")
        score = score + 1
    else:
        print("Wrong answer, the answer was",answer,"!")

Answer 1

默认情况下，input()返回一个字符串。因此，即使您输入12，Player_input也是"12"（字符串）。要使Player_input成为int eger，只需输入Player_input = int(Player_input)即可。 int()函数接受任何数据值，并尝试将其转换为整数。但是，如果它无法转换，例如尝试转换"not num"，则会引发ValueError为了防止这种情况，您可以将其包装在try/except语句中。

程序不会比较球员答案的真实答案

1 个答案: