我目前遇到了一个问题。我正在尝试输入一个我想要总计的硬币数量的数字，并分别显示美元总数和总分数而不使用“div”指令。这基本上就是我的整个计划：
; Assembler directives
.586 ;accept instructions for 586
.MODEL FLAT ;generate code for flat memory
INCLUDE io.h ;header file for input/output
.STACK 4096 ;reserve 4096-byte stack
.DATA ; Data section begins here: reserve storage for data
numPromptP BYTE "How many pennies do you have?", 0 ;Prompt string for pennies
numPromptN BYTE "How many nickles do you have?", 0 ;Prompt string for nickles
numPromptD BYTE "How many dimes do you have?", 0 ;Prompt string for dimes
numPromptQ BYTE "How many quarters do you have?", 0 ;Prompt string for quarters
asciiInNum BYTE 3 DUP (?) ;ASCII input for an integer
outCoinLabel BYTE "Coin Information", 0 ;string to display total amount of coins
asciiOutCoinString BYTE "Number of coins: ", 10 DUP (?), 0dh, 0ah, "Dollars: ", 10 DUP (?), 0dh, 0ah, "Cents: ", 10 DUP (?), 0
intP DWORD ? ;pennies 32-bit integer
intN DWORD ? ;nickles 32-bit integer
intD DWORD ? ;dimes 32-bit integer
intQ DWORD ? ;quarters 32-bit integer
coinTotal DWORD ? ;Coin Total 32-bit integer
multiplier DWORD ? ;32-bit integer to store value for multiplication
dollarTotal DWORD ? ;32-bit integer to store dollar value of coins
centTotal DWORD ? ;32-bit integer to store cent value of coins
.CODE ; Code section begins here
_MainProc PROC ;main procedure starts here
;read ASCII input for pennies, convert to 2's comp, add to coin total, and store in memory
input numPromptP, asciiInNum, 3 ;prompt for, read, and store ASCII characters
atod asciiInNum ;convert ASCII to 2's comp and store in EAX
mov coinTotal, eax ;move amount of pennies to coinTotal
mov intP, eax ;store pennies value in memory
;read ASCII input for nickles, convert to 2's comp, add to coin total, multiply by 5, and store in memory
input numPromptN, asciiInNum, 3 ;prompt for, read, and store ASCII characters
atod asciiInNum ;convert ASCII to 2's comp and store in EAX
add coinTotal, eax ;add amount of nickles to coinTotal
mov multiplier, 5
mul multiplier ;multiply value in EAX by 5
mov intN, eax ;store nickles value in memory
;read ASCII input for dimes, convert to 2's comp, add to coin total, multiply by 10, and store in memory
input numPromptD, asciiInNum, 3 ;prompt for, read, and store ASCII characters
atod asciiInNum ;convert ASCII to 2's comp and store in EAX
add coinTotal, eax ;add amount of dimes to coinTotal
mov multiplier, 10
mul multiplier ;multiply value in EAX by 10
mov intD, eax ;store 2's comp in memory
;read ASCII input for quarters, convert to 2's comp, add to coin total, multiply by 25, and store in memory
input numPromptQ, asciiInNum, 3 ;prompt for, read, and store ASCII characters
atod asciiInNum ;convert ASCII to 2's comp and store in EAX
add coinTotal, eax ;add amount of dimes to coinTotal
mov multiplier, 25
mul multiplier ;multiply value in EAX by 25
mov intQ, eax ;store 2's comp in memory
;Add up total dollar amount from coins, and store in memory
mov eax, intP
add eax, intN
add eax, intD
add eax, intQ
mov dollarTotal, eax
mov centTotal, eax
dtoa asciiOutCoinString+16, coinTotal
dtoa asciiOutCoinString+37, dollarTotal
dtoa asciiOutCoinString+56, centTotal
output outCoinLabel, asciiOutCoinString
mov eax, 0 ;exit with return code 0
ret
_MainProc ENDP ;end of main procedure
END ;end of source code
我的问题是......有没有办法获得存储在eax寄存器中的字节，这样我就可以说“在Eax + 5个内存位置取字节并存入”dollarTotal“和” byte存储在EAX +6和EAX +7内存位置，并存储在“centTotal”中。我已经阅读了有关间接寄存器模式的内容，但我对它并不太熟悉，所以我只需要指向正确的方向。我有解决方案，我只是不知道如何实现它！我目前的节目打印（如果我指出4便士，4角钱，4个镍币和4个季度）：
Number of coins: 16
Dollars: 164 (I want this to say "1")
Coins: 164 (I want this to say "64")
答案 0 :(得分：1)
我想出了一个独特的解决方案！基本上，通过取1/100 * 2 ^ 32，将此十进制转换为十六进制，并将此十六进制存储在内存中的乘数中。我可以这样做：
imul multiplier
将eax中的美元金额乘以1/100 * 2 ^ 32，并且它基本上是乘以＆＃34;的分数，并将100的位置存储在edx和在eax休息。例如，如果我有＆＃34; 164＆＃34;在乘法之前存储在eax中，并执行该指令。这将导致1存储在edx中，其余的存储在eax中。
答案 1 :(得分：0)
这是一个通过首先在一个临时字符串中转换dollartotal然后有选择地复制出美元和美分的字符来分离美元和美分的解决方案。
dtoa tempstring, dollarTotal
mov al,[tempstring]
mov [asciiOutCoinString+37], al ;"1"
mov ax,[tempstring+1]
mov [asciiOutCoinString+56], ax ;"64"