我有一个名为rbp
的data.frame,它包含一个如下列的列:
>rbp
V1
dd_smadV1_39992_0_1
Protein: AGBT(Dm)
Sequence Position
234
290
567
126
Protein: ATF1(Dm)
Sequence Position
534
890
105
34
128
301
Protein: Pox(Dm)
201
875
453
*********************
dd_smadv1_9_02
Protein: foxc2(Mm)
Sequence Position
145
987
345
907
Protein: Lor(Hs)
876
512
我想丢弃序列位置并仅提取特定细节,如序列名称和相应的蛋白质名称,如下所示:
dd_smadV1_39992_0_1 AGBT(Dm);ATF1(Dm);Pox(Dm)
dd_smadv1_9_02 foxc2(Mm);Lor(Hs)
我在R中尝试了以下代码,但失败了:
library(gsubfn)
Sub(rbp$V1,"Protein:(.*?) ")
请有人指导我。
答案 0 :(得分:1)
这是一种方法:
m <- gregexpr("Protein: (.*?)\n", x <- strsplit(paste(rbp$V1, collapse = "\n"), "*********************", fixed = TRUE)[[1]])
proteins <- lapply(regmatches(x, m), function(x) sub("Protein: (.*)\n", "\\1", x))
names <- sub(".*?([A-z0-9_]+)\n.*", "\\1", x)
sprintf("%s %s", names, sapply(proteins, paste, collapse = ";"))
# [1] "dd_smadV1_39992_0_1 AGBT(Dm);ATF1(Dm);Pox(Dm)"
# [2] "dd_smadv1_9_02 foxc2(Mm);Lor(Hs)