Question

我从2天前的一本书中学习c ++，其中一个练习令我感到困惑。我觉得我做得对，但这本书没有教我这个。有人可以告诉我如何处理我的代码，使其只打印（用户输入的）和b（用户输入）的偶数。

int a, b;

cout << "What number would you like to start counting at?" << endl;
cin >> a;

cout << "What number would you like to end at?" << endl;
cin >> b;

while (a <= b){
    if (a % 2 == 0){
        cout << a << endl;
        a++;
    }
}

return 0;

Answer 1

即使不均匀，您也必须提高a的值：

int a, b;

cout << "What number would you like to start counting at?" << endl;
cin >> a;

cout << "What number would you like to end at?" << endl;
cin >> b;

while (a <= b){
    if (a % 2 == 0){
        cout << a << endl;
    }
    a++;
}

return 0;

Answer 2

如果a是偶数，那么您的代码只会增加a，这样做不好，您希望a++循环中的while，但if a is even之外的{{1}} {1}}

我无法弄清楚如何打印偶数

2 个答案: