我正在尝试使用php设置mxl产品Feed,但这对我来说是全新的,我希望有人可以提供帮助。我附上了我当前的代码,其中列出了具有多个sku的产品ID。
输出如下:
Product_ID 1
SKU 1234
Product_ID1
SKU12345
我试图使用foreach
看起来像这样Product_ID 1
SKU 1234
SKU 12345
这是我目前的代码
while ($row = $st->fetch()) {
$xml .= "\t\t\t<Product_ID>".$row['product_id']."</Product_ID>\r\n";
$xml .= "\t\t\t<Manufacture>".$row['manufactures_name']."</Manufacture>\r\n";
$xml .= "\t\t\t<Product_Name>".$row['product_name']."</Product_Name>\r\n";
$xml .= "\t\t\t<Product_Category>".$row['product_type']."</Product_Category>\r\n";
$xml .= "\t\t\t<SKU>".$row['sku']."</SKU>\r\n";
$xml .= "\t\t\t<UPC>".$row['upc']."</UPC>\r\n";
$xml .= "\t\t\t<Base_Price>".$row['base_price']."</Base_Price>\r\n";
$xml .= "\t\t\t<QtyAvailable>".$row['quantity']."</QtyAvailable>\r\n";
}
我试图在这里添加foreach
,但我没有线索。
while ($row = $st->fetch())
$xml .= "\t\t\t<Product_ID>".$row['product_id']."</Product_ID>\r\n";
foreach ('product_id' == 'product_id');
$xml .= "\t\t\t<SKU>".$row['sku']."</SKU>\r\n";
$xml .= "\t\t\t<Manufacture>".$row['manufactures_name']."</Manufacture>\r\n";
$xml .= "\t\t\t<Product_Name>".$row['product_name']."</Product_Name>\r\n";
$xml .= "\t\t\t<Product_Category>".$row['product_type']."</Product_Category>\r\n";
$xml .= "\t\t\t<UPC>".$row['upc']."</UPC>\r\n";
$xml .= "\t\t\t<Base_Price>".$row['base_price']."</Base_Price>\r\n";
$xml .= "\t\t\t<QtyAvailable>".$row['quantity']."</QtyAvailable>\r\n";
}
答案 0 :(得分:1)
如果您正在尝试生成XML,我建议您使用PHP的SimpleXML库,因为它可以提供更大的灵活性,并且读取更清晰。有关文档,请参阅http://php.net/simplexml。
文档示例:
#include <Rcpp.h>
// [[Rcpp::export]]
SEXP funx()
{
/* creating a pointer to a vector<int> */
std::vector<int>* v = new std::vector<int> ;
v->push_back( 1 ) ;
v->push_back( 2 ) ;
/* wrap the pointer as an external pointer */
/* this automatically protected the external pointer from R garbage
collection until p goes out of scope. */
Rcpp::XPtr< std::vector<int> > p(v, true) ;
/* return it back to R, since p goes out of scope after the return
the external pointer is no more protected by p, but it gets
protected by being on the R side */
return( p ) ;
}