Question

假设我有一个如下表：

员工否|工资类型|工资|公司代码|

对于每个员工不，我想创建一个如下表格（我知道工资类型的数量）

独特员工否|总和（工资类型1）|总和（工资类型2）|公司代码

我正在使用以下代码，但它不起作用...

select [Pers No ] ,["Co   Code"],[Company Code],
from [dbo].[Wages] as a 
    left join(
        select sum([[Total Wages])as [Total Wage Type 1 for Aug] 
        from [dbo].[Wages] 
        where [Wage Description] ='Wage Type 1' 
    ) as b on a.[Pers No ]=b.[Pers No ]
    left join(
        select sum([Total Wages]) as [Total Wage Type 2 for Aug] 
        from [dbo].[Wages] 
        where [Wage Description]='Wage Type 2'
    ) as c on b.[Pers No ] =c.[Pers No ]
group by[Pers No ], ["Co   Code"],[Company Code]
into [Total Wages Group by Pers No]

基本上，我想得到每个员工每个工资类型组的工资总额。我的想法是最初按员工分组，然后在单个选择语句中获得每种工资的总和，但这不起作用。这就是为什么我现在使用左连接...但它不能正常工作。

Answer 1

使用条件聚合可能有效：

select 
  [Pers No ],[Company Code],
  sum(case when [Wage Description] = 'OW for CPF' then [PwC_Totals] else 0 end) as [Total OW for Aug] ,
  sum(case when [Wage Description] = 'AW for CPF' then [PwC_Totals] else 0 end) as [Total AW for Aug] 
from [dbo].[OW and  AW - aug 14_cleaned] 
group by [Pers No ], [Company Code]

表格中的列名称并非全部清除，因此您可能需要对其进行调整。

如何组合内连接，子查询，求和条件

1 个答案: