我创建了一个分数示例来演示我的问题。
会员可以奖励其他会员积分,我正在尝试构建一个查询,该查询将显示用户拥有的积分和用户提供的积分。
成员,
+----+----------+
| id | username |
+----+----------+
| 1 | user1 |
| 2 | user2 |
| 3 | user3 |
+----+----------+
点,
+-------+--------+--------+
| IDFor | IDFrom | Pointz |
+-------+--------+--------+
| 1 | 2 | 5 |
| 1 | 2 | 5 |
| 3 | 1 | 2 |
+-------+--------+--------+
我正在寻找的回报是,
+-----------+--------+-------+
| username | Pointz | Given |
+-----------+--------+-------+
| user1 | 10 | 2 |
| user2 | 0 | 10 |
| user3 | 2 | 0 |
+-----------+--------+-------+
我的查询都返回,
+-----------+--------+-------+
| username | Pointz | Given |
+-----------+--------+-------+
| user1 | 10 | 4 |
| user2 | 0 | 10 |
| user3 | 2 | 0 |
+-----------+--------+-------+
SELECT a.`username`, sum(a.`Pointz`), sum(b.`Pointz`) FROM
(SELECT * FROM `members`
LEFT JOIN `Example`.`Points` AS p ON `members`.`id` = p.`IDFor` ) AS a
LEFT JOIN
(SELECT * FROM `members`
LEFT JOIN `Example`.`Points` AS n ON `members`.`id` = n.`IDFrom` ) AS b
ON a.id = b.id
GROUP BY a.`id`
SELECT `members`.`username`,sum(p.`Pointz`),sum(n.`Pointz`)
FROM `members`
LEFT JOIN `Example`.`Points` as p ON p.`IDFor` = `members`.`id`
LEFT JOIN `Example`.`Points` as n ON n.`IDFrom` = `members`.`id`
GROUP BY `members`.`id`
似乎是一个常见的问题,弹出但没有找到解决方案,我所有其他类似问题的尝试都没有很好地结束,谢谢大家。
答案 0 :(得分:1)
这就是你想要的
select a.username, ifnull(Pointz, 0) Pointz, ifnull(Given, 0) Given from
(SELECT id, `username`, sum(`Pointz`) Pointz FROM `members`
LEFT JOIN `Points` ON `members`.`id` = `Points`.`IDFor` group by id) a
left join
(SELECT id, `username`, sum(`Pointz`) Given FROM `members`
LEFT JOIN `Points` ON `members`.`id` = `Points`.`IDFrom` group by id) b
on a.id = b.id
答案 1 :(得分:1)
尝试:
SELECT m.username,
COALESCE( pr.preceived, 0 ) as Pointz,
COALESCE( pg.pgiven, 0 ) as Given
FROM members m
LEFT JOIN ( SELECT IDFor, sum(pointz) as preceived
FROM Points
GROUP BY IDFor ) pr
ON m.id = pr.IDFor
LEFT JOIN ( SELECT IDFrom, sum(pointz) as pgiven
FROM Points
GROUP BY IDFrom ) pg
ON m.id = pg.IDFrom
答案 2 :(得分:1)
试试这个:
SELECT m.`username`,
ifnull((SELECT sum(`Pointz`) FROM Points p
WHERE p.IDFor = m.id ), 0),
ifnull((SELECT sum(`Pointz`) FROM Points p
WHERE p.IDFrom = m.id ), 0)
FROM Members m