我尝试创建一个返回不同字符串的函数,具体取决于boolean元组中的值
chooseAction :: (Bool , Bool , Bool , Bool) -> String
chooseAction (isJump ,isAcceleration ,isDeceleration ,isSpeedOk)
| (True ,False, False, False) = "JUMP"
| (False ,True, False, False) = "SPEED"
| (False ,False, True, False) = "SLOW"
| (False ,False ,False, True) = "WAIT"
然而,这不会编译:
Couldn't match expected type `Bool' with actual type `(Bool, Bool, Bool, Bool)' In the expression: (True, False, False, False) In a stmt of a pattern guard for an equation for `chooseAction': (True, False, False, False) In an equation for `chooseAction': chooseAction (isJump, isAcceleration, isDeceleration, isSpeedOk) | (True, False, False, False) = "JUMP" | (False, True, False, False) = "SPEED" | (False, False, True, False) = "SLOW" | (False, False, False, True) = "WAIT"
在定义这样的函数时我做错了什么?
答案 0 :(得分:5)
守卫表达式必须评估为Bool
值,但在您的情况下,您有一些Bools元组。这就是它抛出错误的原因
Couldn't match expected type `Bool'
with actual type `(Bool, Bool, Bool, Bool)'
最好定义像这样的函数
chooseAction::(Bool, Bool, Bool, Bool) -> String
chooseAction (True, False, False, False) = "JUMP"
chooseAction (False, True, False, False) = "SPEED"
chooseAction (False, False, True, False) = "SLOW"
chooseAction (False, False, False, True) = "WAIT"
此外,您没有涵盖所有案件。所以,你可以像这样覆盖
chooseAction tuple_of_bools = "NONE"
如果所有模式都不匹配,则执行最后一个模式以获得NONE
。或者,如果您希望按照它的方式定义它,那么只需更改比较,就像这样
chooseAction:: (Bool, Bool, Bool, Bool) -> String
chooseAction bools
| bools == (True ,False, False, False) = "JUMP"
| bools == (False ,True, False, False) = "SPEED"
| bools == (False ,False, True, False) = "SLOW"
| bools == (False ,False ,False, True) = "WAIT"
| otherwise = "NONE"
答案 1 :(得分:3)
使用模式匹配:
chooseAction :: (Bool , Bool , Bool , Bool) -> String
chooseAction (True ,False, False, False) = "JUMP"
chooseAction (False ,True, False, False) = "SPEED"
chooseAction (False ,False, True, False) = "SLOW"
chooseAction (False ,False ,False, True) = "WAIT"
chooseAction _ = error "This should not happen" -- if sequence is something else