我有一组具有唯一节点的连接边。它们使用父节点连接。请考虑以下示例代码和插图:
CREATE TABLE network (
node integer PRIMARY KEY,
parent integer REFERENCES network(node),
length numeric NOT NULL
);
CREATE INDEX ON network (parent);
INSERT INTO network (node, parent, length) VALUES
(1, NULL, 1.3),
(2, 1, 1.2),
(3, 2, 0.9),
(4, 3, 1.4),
(5, 4, 1.6),
(6, 2, 1.5),
(7, NULL, 1.0);
视觉上,可以识别两组边。如何使用PostgreSQL 9.1识别这两个组,并length
求和?显示预期结果:
edges_in_group | total_edges | total_length
----------------+-------------+--------------
{1,2,3,4,5,6} | 6 | 7.9
{7} | 1 | 1.0
(2 rows)
我甚至不知道从哪里开始。我需要自定义聚合或窗口功能吗?我可以使用WITH RECURSIVE
迭代收集连接的边缘吗?我的真实案例是245,000个边缘的流网络。我希望edges_in_group
的最大数量小于200,以及几百个聚合组(行)。
答案 0 :(得分:4)
递归查询是要走的路:
with recursive tree as (
select node, parent, length, node as root_id
from network
where parent is null
union all
select c.node, c.parent, c.length, p.root_id
from network c
join tree p on p.node = c.parent
)
select root_id, array_agg(node) as edges_in_group, sum(length) as total_length
from tree
group by root_id;
重要的是在每次递归中保留根节点的id,以便您可以在最终结果中按该id进行分组。