我正在寻找一种方法来做到这一点......
SELECT FirstName, LastName, Split(AddressBlock, ' ', 1), Split(AddressBlock, ' ', 2), PostCode
FROM Contacts
我要传递的论据是......
我似乎能够找到一些关于互联网分割功能的例子,但是它们会返回一个包含整个分割部分的表格。
我的SQL技能不是很好,所以我需要答案才能过于简单。 我总是使用nvarchar数据,并且该函数需要可重用。
答案 0 :(得分:4)
如果您想要一个用户定义的函数来执行此操作,这应该可行。不是那么漂亮,但是......
CREATE FUNCTION dbo.SplitStringPart (
@input nvarchar(MAX),
@separator nvarchar(10),
@index int
) RETURNS nvarchar(MAX)
BEGIN
DECLARE @counter int,
@position int,
@oldposition int,
@separatorlength int,
@result nvarchar(MAX)
SET @separatorlength = DATALENGTH(@separator) / 2
IF @separatorlength = 0 RETURN NULL
SET @result = NULL
SET @counter = 1
SET @position = -2
WHILE (@counter <= @index)
BEGIN
SET @oldposition = @position
SET @position = CHARINDEX(@separator, @input, @position + 1)
IF @position = 0 AND @counter < @index
BEGIN
SET @oldposition = 0
BREAK
END
SET @counter = @counter + 1
END
IF @oldposition = 0 AND @position = 0
RETURN NULL
ELSE IF @oldposition < 0
BEGIN
IF @position = 0 AND @index = 1
SET @result = @input
ELSE
SET @result = SUBSTRING(@input, 0, @position)
END
ELSE IF @position <= 0
SET @result = SUBSTRING(@input, @oldposition + @separatorlength, LEN(@input) - @oldposition - @separatorlength)
ELSE
SET @result = SUBSTRING(@input, @oldposition + @separatorlength, @position - @oldposition - @separatorlength)
RETURN @result
END
GO
答案 1 :(得分:1)
它不漂亮,但是将它添加到SQL语句中它应该可以工作:
CASE
WHEN charindex(' ', substring(AddressBlock, (charindex(' ', AddressBlock) + 1), len(AddressBlock))) > 0 THEN substring(AddressBlock, (charindex(' ', AddressBlock) + 1), charindex(' ', substring(AddressBlock, (charindex(' ', AddressBlock) + 1), len(AddressBlock))) - 1)
ELSE substring(AddressBlock, (charindex(' ', AddressBlock) + 1), len(AddressBlock))
END AS 'Address 1',
CASE WHEN charindex(' ', substring(AddressBlock, (charindex(' ', AddressBlock) + 1), len(AddressBlock))) > 0 THEN substring(AddressBlock, charindex(' ', AddressBlock) + charindex(' ', substring(AddressBlock, (charindex(' ', AddressBlock) + 1), len(AddressBlock))) + 1, Len(AddressBlock))
ELSE ''
END AS 'Address 2'
答案 2 :(得分:0)
这是我的答案版本。这是更快更强大的。不需要对子串,charindex等进行讨论。
CREATE FUNCTION [dbo].[SplitArray]
(
@RowToSplit nvarchar(MAX),
@Delimeter nvarchar(MAX)
)
RETURNS @RtnValue table (ID bigint IDENTITY, Data nvarchar(MAX))
AS
BEGIN
DECLARE @xml xml
SET @xml = '<field>' + REPLACE(@RowToSplit, @Delimeter, '</field><field>') + '</field>'
INSERT INTO @RtnValue(data)
SELECT tbl.c.value('.','nvarchar(max)')
FROM @xml.nodes('/field') tbl(c)
RETURN
END
您只需在表格中使用结果拆分值,如下所示:
SELECT Data FROM dbo.SplitArray('this is great',' ')
这将返回:
Data
============
this
is
great