Question

我正在努力将我的代码输出写入txt文件，同时保持格式。这是代码：

import os

# Compute matrix
titles = ['Filename', 'Date']
matrix = [titles]
for directory, __, files in os.walk('MY_DIRECTORY'): # replace with actual directory path
    for filename in files:
        with open(os.path.join(directory, filename)) as f:
            name, date = f.readline().strip().split()
            print(name)
            row = [name, date.split('.')[-1]]
            for line in f:
                header, value = line.strip().split(':')
                if len(matrix) == 1:
                    titles.append(header)
                row.append(value)        
        matrix.append(row)

# Work out column widths
column_widths = [0]*len(titles)
for row in matrix:
    for column, data in enumerate(row):
        column_widths[column] = max(column_widths[column], len(data))
formats = ['{:%s%ss}' % ('^' if c>1 else '<', w) for c, w in enumerate(column_widths)]


for row in matrix:
    for column, data in enumerate(row):
        print(formats[column].format(data)), 
    print

这个的输出如下所示，其中我在第一行中选择了单词，并为我正在处理的每个文件添加了一行：

Filename Date ('in', 'usd', 'millions') ('indd', 'zurich', 'financial') ('table', 'in', 'usd') ('group', 'executive', 'committee') ('years', 'ended', 'december')
COMPANYA 2011            144                          128                        121                           96                                88              
COMPANYA 2012             1                            2                          3                             4                                5

现在我试着把它写成一个txt文件，但我没弄清楚，有什么建议吗？

Answer 1

如果你真的只是想把你正在打印的字符串写到一个文件上，那么它不会比这更多：

out = ""

for row in matrix:
    for column, data in enumerate(row):
        out += formats[column].format(data)
    out += "\n"

with open("out.txt","wt") as file:
    file.write(out)

Python - 将矩阵写入txt文件，保持格式化

1 个答案: