Question

我使用Parse.com作为后端服务。当有人拨打twilio号码时，我想检测云代码中的来电号码，然后查询相应的用户电话号码。我能够通过request.param（＆＃39; From＆＃39;）获取呼叫者号码但是我无法查询该用户。我尝试在多种形式的/ hello函数中查询，但它不起作用。我使用了同样的查询集，适用于其他云功能。该查询记录为未定义。为什么会这样？ xcode的：

 NSString *callString = [NSString stringWithFormat:@"telprompt://twilioNumber"];

 [[UIApplication sharedApplication] openURL:[NSURL URLWithString:callString]];

解析云代码

    //Someone calling twilio number
    app.get('/hello', function(request, response) {
    var twiml = new twilio.TwimlResponse('');

var query = new Parse.Query(Parse.User);
  query.equalTo("PhoneNumber", request.param('From'));
    query.first({
            success: function(result) {
            var foundusr = result;
        var receiver = foundusr.get("Receiver");
twiml.dial({callerId:'twilioNumber'}, receiver);
},
            error: function(error) {response.error("Error updating user passcode"); 
});    
        response.type('text/xml');
        response.send(twiml.toString(''));
        });
        app.listen();

Answer 1

它不起作用，因为以下代码不在query.first函数

中

twiml.dial({callerId:'twilioNumber'}, receiver);
                response.type('text/xml');

所以正确的方法是

//Someone calling twilio number
        app.get('/hello', function(request, response) {
        var twiml = new twilio.TwimlResponse('');

var query = new Parse.Query(Parse.User);
  query.equalTo("PhoneNumber", request.param('From'));
    query.first({
            success: function(result) {
            var foundusr = result;
            var receiver = foundusr.get("Receiver");
            twiml.dial({callerId:'twilioNumber'}, receiver);
            response.type('text/xml');
        response.send(twiml.toString(''));
},
            error: function(error) {response.error("Error updating user passcode"); 
});    

        });
        app.listen();

调用Twilio编号时查询用户表

1 个答案: