Question

我遵循XMLList，

<party/> <party/> <party/> <party>A</party> <party>B</party> <party>C</party> <party>A</party> <party>B</party> <party>C</party> <party>D</party> <party>E</party> <party>D</party> <party>A</party> <party/> <party>C</party>

我想消除空白节点并使ArrayCollection像（个别方的数量），

tArr = new ArrayCollection（[{Party：“A”，Count：3}， {派对：“B”，伯爵：2}， {党：“C”，伯爵：3}， {派对：“D”，伯爵：2}， {派对：“E”，伯爵：1}， ]）;

提前致谢。

Answer 1

这是未经测试的，可能不是最有效的，但应该有效：

var partyDict:Dictionary = new Dictionary();
var parties:ArrayCollection = new ArrayCollection();

var xml:XML = <root><party/><party/><party/><party>A</party><party>B</party><party>C</party><party>A</party><party>B</party><party>C</party><party>D</party><party>E</party><party>D</party><party>A</party><party/><party>C</party></root>;

for each (var p:XML in xml.party) {
    var val:String = p.toString();
    if ((val != null) && StringUtil.trim(val).length > 0) {
        if (partyDict[val] != null) {
            partyDict[val] = (partyDict[val] as int) + 1; // may simply be able to do partyDict[val]++;
        } else {
            partyDict[val] = 1;
        }
    }
}

for (var key:Object in partyDict) {
    var o:Object = new Object();
    o.Party = key;
    o.Count = partyDict[key];
    parties.addItem(o);
}

Answer 2

如果您有可能派对的列表，那就是：

var partiesObjs:ArrayCollection = new ArrayCollection();

var xml:XML = <root><party/><party/><party/><party>A</party><party>B</party><party>C</party><party>A</party><party>B</party><party>C</party><party>D</party><party>E</party><party>D</party><party>A</party><party/><party>C</party></root>;
var parties:Array = ["A","B","C","D"]

for each(var p:String in parties){
  var count:int = xml..party.(toString() == p).length()
  partiesObjs.addItem( {Party:p, Count:count} )
}

如何计算XMLList中的重复项并将它们分配到ArrayCollection中？

2 个答案: