计算数组中的重复键并将它们相加

Question

我试图遍历确定的论坛帖子的所有页面，并获得每个用户的帖子总数，但我很难理解每次在用户名重复内容时如何求和阵列。

这是我的代码：

for ($x = 1; $x <= 5; $x++) {

    $ch = curl_init('http://myforum.com/thread-123?&page=' . $x);

    curl_setopt_array($ch, array(
        CURLOPT_HEADER => TRUE,
        CURLOPT_RETURNTRANSFER => TRUE
    ));

    $response = curl_exec($ch);

    preg_match_all('/me\">[\s]+<a href=\"([^\"]+)\">([^<]+)/i', $response, $users);
    preg_match_all('/image_avatar\" src=\"([^\"]+)"/i', $response, $avatar);


    $q = count($users[1]);

    for ($i = 0; $i < $q; $i++) {
        ///////count how many times the user was inside the array///////
        //$totalPosts = ?
        ///////count how many times the user was inside the array///////

        print '-----<br /><img src="'.$avatar[1][$i].'" /><br />User: ' . $users[2][$i] . '<br />Total Posts: ' . $totalPosts . '-----<br />';        

    }


}

解决方案，谢谢@u_mulder

$all_users = array();
for ($x = 1; $x <= 5; $x++) {

    $ch = curl_init('http://myforum.com/thread-123?&page=' . $x);

    curl_setopt_array($ch, array(
        CURLOPT_HEADER => TRUE,
        CURLOPT_RETURNTRANSFER => TRUE
    ));

    $response = curl_exec($ch);

    preg_match_all('/me\">[\s]+<a href=\"([^\"]+)\">([^<]+)/i', $response, $users);
    preg_match_all('/image_avatar\" src=\"([^\"]+)"/i', $response, $avatar);


    $all_users = array_merge($all_users, $users[2]);


}
function aprint($arr, $return = false) {
    arsort($arr);
    $wrap = '<div style=" white-space:pre; position:absolute; top:10px; left:10px; height:200px; width:100px; overflow:auto; z-index:5000;">';
    $wrap = '<pre>';
    $txt = preg_replace('/(\[.+\])\s+=>\s+Array\s+\(/msiU','$1 => Array (', print_r($arr,true));

    if ($return) return  $wrap.$txt.'</pre>';
    else echo $wrap.$txt.'</pre>';
}

$res = array_icount_values ($all_users);
$res2 = aprint($res);
print_r($res2); 

function array_icount_values($arr,$lower=true) { 
     $arr2=array(); 
     if(!is_array($arr['0'])){$arr=array($arr);} 
     foreach($arr as $k=> $v){ 
      foreach($v as $v2){ 
      if($lower==true) {$v2=strtolower($v2);} 
      if(!isset($arr2[$v2])){ 
          $arr2[$v2]=1; 
      }else{ 
           $arr2[$v2]++; 
           } 
    } 
    } 
    return $arr2; 
}

示例输出（用户名=＆gt;帖子总数）也按总帖子排序：

Array
(
    [user 1] => 35
    [user 2] => 11
    [user 3] => 11
    [user 4] => 8
    [user 5] => 5
    [user 6] => 4
    [user 7] => 3
    [user 8] => 2
    [user 9] => 2
    [user 10] => 2
    [user 11] => 2
    [user 12] => 1
    [user 13] => 1
    [user 14] => 1
    [user 15] => 1
    [user 16] => 1
    [user 17] => 1
    [user 18] => 1
    [user 19] => 1
    [user 20] => 1
    [user 21] => 1
    [user 22] => 1
    [user 23] => 1
    [user 24] => 1
    [user 25] => 1
    [user 26] => 1
)

Answer 1

要计算数组中项目的频率，您可以使用array_count_values函数。

您提供的数组代码示例：

$users = array('user found 1', 'user found 2', 'user found 3', 'user found 1', 'user found 2', 'user found 1', 'user found 1');
print_r(array_count_values($users));

结果是：

Array ( [user found 1] => 4 [user found 2] => 2 [user found 3] => 1 ) 

<强>更新 好吧，如果你有不同的页面，那么尝试这样的事情：

$all_users = array();
for ($x = 1; $x <= 5; $x++) {
    // ....
    preg_match_all('/me\">[\s]+<a href=\"([^\"]+)\">([^<]+)/i', $response, $users);

    $all_users = array_merge($all_users, $users[1]);
}
print_r(array_count_values($all_users));