如何使用应用程序工厂正确设置flask-admin视图？

时间：2015-02-13 21:05:40

标签： python flask flask-sqlalchemy flask-admin

我正试图针对用户＆＃39;设置flask-admin model views with SQLAlchemy。和＃角色＆＃39;楷模。我没有获得功能管理员视图：

ValueError: Invalid model property name <class 'app.models.Role'>.desc

堆栈追踪：

Traceback (most recent call last):

File "/Users/dbg/Projects/Python/Current/ziff/flaskbase/manage.py", line 18, in <module>
    app = create_app(os.getenv('APP_CONFIG') or 'default')
  File "/Users/dbg/Projects/Python/Current/ziff/flaskbase/app/__init__.py", line 49, in create_app
    admin.add_view(RoleAdmin(Role, db.session))
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/contrib/sqla/view.py", line 288, in __init__
    menu_icon_value=menu_icon_value)
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/model/base.py", line 570, in __init__
    self._refresh_cache()
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/model/base.py", line 640, in _refresh_cache
    self._refresh_forms_cache()
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/model/base.py", line 580, in _refresh_forms_cache
    self._create_form_class = self.get_create_form()
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/model/base.py", line 856, in get_create_form
    return self.get_form()
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/model/base.py", line 848, in get_form
    return self.scaffold_form()
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/contrib/sqla/view.py", line 607, in scaffold_form
    extra_fields=self.form_extra_fields)
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/contrib/sqla/form.py", line 427, in get_form
    for name, p in properties:
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/contrib/sqla/form.py", line 422, in <genexpr>
    properties = ((x, find(x)) for x in only)
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/contrib/sqla/form.py", line 419, in find
    raise ValueError('Invalid model property name %s.%s' % (model, name))
ValueError: Invalid model property name <class 'app.models.Role'>.desc

我正在使用带有蓝图的烧瓶应用工厂方法。这是我的申请工厂。

我的__init__.py文件，我尝试在第49行创建视图：

from flask import Flask
from flask.ext.bootstrap import Bootstrap
from flask.ext.mail import Mail
from flask.ext.moment import Moment
from flask.ext.sqlalchemy import SQLAlchemy
from flask.ext.security import Security
from flask.ext.admin import Admin
from flask_s3 import FlaskS3
from flask.ext.cdn import CDN
from flask.ext.assets import Environment
from flask.ext.assets import PythonLoader as PythonAssetsLoader
from config import config


# app setup
bootstrap = Bootstrap()
mail = Mail()
moment = Moment()
db = SQLAlchemy()
security = Security()
admin = Admin()
s3 = FlaskS3()
cdn = CDN()
assets_env = Environment()



def create_app(config_name):
  app = Flask(__name__)
  app.config.from_object(config[config_name])
  app.name = app.config['APP_NAME']
  config[config_name].init_app(app)

  from .models import user_datastore, User, Role
  from .auth.views import RoleAdmin, UserAdmin

  bootstrap.init_app(app)
  mail.init_app(app)
  moment.init_app(app)
  db.init_app(app)
  security.init_app(app, user_datastore)
  admin.init_app(app)
  s3.init_app(app)
  cdn.init_app(app)
  assets_env.init_app(app)

  # Here's where I'm trying to create the views
  admin.add_view(RoleAdmin(Role, db.session))
  admin.add_view(UserAdmin(User, db.session))

  from . import assets
  assets_loader = PythonAssetsLoader(assets)
  for name, bundle in assets_loader.load_bundles().iteritems():
    assets_env.register(name, bundle)

  # attach asset bundles, routes, and custom error pages here
  from main import main as main_blueprint
  app.register_blueprint(main_blueprint)
  import main.assets as main_assets
  assets_loader = PythonAssetsLoader(main_assets)
  for name, bundle in assets_loader.load_bundles().iteritems():
    assets_env.register(name, bundle)

  from auth import auth as auth_blueprint
  app.register_blueprint(auth_blueprint)


  return app

我的ModelView类：

from flask.ext.admin.contrib.sqla import ModelView

__author__ = 'dbg'

class RoleAdmin(ModelView):
  column_display_pk = True
  form_columns = ['id', 'desc']

class UserAdmin(ModelView):
  column_display_pk = True
  form_columns = ['id', 'email', 'active', 'last_login_at', 'login_count', 'roles']

修改

Models.py 

from app import db
from flask.ext.security import UserMixin, RoleMixin, SQLAlchemyUserDatastore


roles_users = db.Table('roles_users',
                       db.Column('user_id', db.Integer(), db.ForeignKey('user.id')),
                       db.Column('role_id', db.Integer(), db.ForeignKey('role.id')))


class Role(db.Model, RoleMixin):
  id = db.Column(db.Integer(), primary_key=True)
  name = db.Column(db.String(80), unique=True)
  description = db.Column(db.String(255))


class User(db.Model, UserMixin):
  id = db.Column(db.Integer(), primary_key=True)
  email = db.Column(db.String(256), unique=True)
  password = db.Column(db.String(36))
  active = db.Column(db.Boolean())
  confirmed_at = db.Column(db.DateTime())
  last_login_at = db.Column(db.DateTime())
  current_login_at = db.Column(db.DateTime())
  last_login_ip = db.Column(db.String(45))
  current_login_ip = db.Column(db.String(45))
  login_count = db.Column(db.Integer())
  roles = db.relationship('Role', secondary=roles_users,
                          backref=db.backref('users', lazy='dynamic'))


user_datastore = SQLAlchemyUserDatastore(db, User, Role)

更新

通过此here找到了非常有用的文章good soul。仍然卡住了。新错误。

Traceback (most recent call last):
  File "/Users/dbg/Projects/Python/Current/ziff/flaskbase/manage.py", line 18, in <module>
    app = create_app(os.getenv('APP_CONFIG') or 'default')
  File "/Users/dbg/Projects/Python/Current/ziff/flaskbase/app/__init__.py", line 83, in create_app
    admin.add_view(RoleAdmin(RoleAdmin, db.session))
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/contrib/sqla/view.py", line 288, in __init__
    menu_icon_value=menu_icon_value)
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/model/base.py", line 570, in __init__
    self._refresh_cache()
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/model/base.py", line 632, in _refresh_cache
    self._list_columns = self.get_list_columns()
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/model/base.py", line 708, in get_list_columns
    columns = self.scaffold_list_columns()
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/contrib/sqla/view.py", line 371, in scaffold_list_columns
    for p in self._get_model_iterator():
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/contrib/sqla/view.py", line 310, in _get_model_iterator
    return model._sa_class_manager.mapper.iterate_properties
AttributeError: type object 'RoleAdmin' has no attribute '_sa_class_manager'

2 个答案:

答案 0 :(得分：4)

嗯，这已经过时了，但我就是这样做的：

# Inside app/auth/__init__.py (auth module includes admin):

#...
from app import db
from flask import Blueprint
from .my_custom_model_views import MyModelView
from ..models import MyModel
#...
auth = Blueprint('auth', __name__)
from . import views
#...
auth.custom_model_views = []
auth.custom_model_views += [MyModelView(MyModel, db.session)]
#...
from . import forms

# Inside app/__init__.py
# ...
admin = Admin(name='Name', ...)
# ...
def create_app(config_name):
# ...
    app = Flask(__name__)
    # ...
    admin.init_app(app)
    # And here's the important part
    with app.app_context():
        from .auth import auth as auth_blueprint
        admin.add_views(*auth_blueprint.custom_model_views)

重要的部分是以某种方式存储您要添加的视图（这里，我只是将它们附加到蓝图），然后添加它们与APP上下文。否则，一切都变得狂暴（没有app上下文，可能会多次添加相同的模型，导致在应用程序实例化期间出现丑陋的名称冲突错误。）

值得注意的是，您在此处添加的任何视图都会显示在烧瓶管理菜单中，就好像它是模型视图一样，即使它是其他类型的视图。您可以通过更改视图的is_visible和is_accessible方法来解决此问题。

答案 1 :(得分：1)

这里是使用蓝图的另一种方式：

# app/__init__.py

from flask import Flask
from flask_sqlalchemy import SQLAlchemy
from flask_admin import Admin

db = SQLAlchemy()
admin = Admin(name='my-app', template_mode='bootstrap3')


def create_app():
    app = Flask(__name__)

    db.init_app(app)
    admin.init_app(app)

    # Add the admin panel
    from app.admin import bp as admin_bp
    app.register_blueprint(admin_bp)

    return app

# app/admin/__init__.py

from flask import Blueprint

bp = Blueprint('admin_bp', __name__)

from app.admin import routes

# app/admin/routes.py

from flask_admin.contrib.sqla import ModelView
from app import db, admin
from app.models import City

admin.add_view(ModelView(City, db.session))
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