Question

我正在进行基于文本的冒险，现在想要运行一个随机函数。所有冒险功能都是＆＃34; adv＆＃34;后跟一个3位数字如果我跑go（）我会回来：

IndexError: Cannot choose from an empty sequence

这是因为allAdv仍为空。如果我在shell中逐行运行go（）它可以工作但不在函数中。我错过了什么？

import fight
import char
import zoo
import random

#runs a random adventure
def go():
    allAdv=[]
    for e in list(locals().keys()):
        if e[:3]=="adv":
            allAdv.append(e)
    print(allAdv)
    locals()[random.choice(allAdv)]()


#rat attacks out of the sewer
def adv001():
    print("All of a sudden an angry rat jumps out of the sewer right beneath your feet. The small, stinky animal aggressivly flashes his teeth.")
    fight.report(zoo.rat)

Answer 1

这主要是由于范围问题，当您在locals()中调用go()时，它只打印出此函数中定义的局部变量allDev：

locals().keys()  # ['allDev']

但是如果您在shell中逐行输入以下内容，locals()会包含adv001，因为在这种情况下它们处于同一级别。

def adv001():
    print("All of a sudden an angry rat jumps out of the sewer right beneath your feet. The small, stinky animal aggressivly flashes his teeth.")
    fight.report(zoo.rat)

allAdv=[]
print locals().keys()  #  ['adv001', '__builtins__', 'random', '__package__', '__name__', '__doc__']
for e in list(locals().keys()):
    if e[:3]=="adv":
        allAdv.append(e)
print(allAdv)
locals()[random.choice(allAdv)]()

如果您真的想在go()中获取这些功能变量，可以考虑将locals().keys()更改为globals().keys()

Python：来自locals（）的随机函数，带有已定义的前缀

1 个答案: