Question

我正在运行一个程序，该程序产生以下输出字符串存储在列表中：

['41.6640', '-91.5447\n', '41.6640', '-91.5447\n', '41.6640', '-91.5447\n', '41.6640', '-91.5447\n', '41.6640', '-91.5447\n']

我需要一个简单的代码来从它所在的任何字符串中删除\n。看起来它应该非常简单，但每次我收到错误或最终删除整个字符串。

Answer 1

只是一个简单的列表理解：

myList = [i.rstrip() for i in myList]

Answer 2

In [13]: a = ['41.6640', '-91.5447\n', '41.6640', '-91.5447\n', '41.6640', '-91.5447\n', '41.6640', '-91.5447\n', '41.6640', '-91.5447\n']

In [14]: map(str.rstrip, a) 
Out[14]: 
['41.6640',
 '-91.5447',
 '41.6640',
 '-91.5447',
 '41.6640',
 '-91.5447',
 '41.6640',
 '-91.5447',
 '41.6640',
 '-91.5447']

In [15]: map(float, a) # To convert to float, you don't need rstrip
Out[15]: 
[41.664,
 -91.5447,
 41.664,
 -91.5447,
 41.664,
 -91.5447,
 41.664,
 -91.5447,
 41.664,
 -91.5447]

Answer 3

遍历您的元素并检查是否＆＃34; \＆＃34;在那里，然后像这样绑它：

for n in my_list:
   if "\\n" in n:
      n = n[0:len(n) - 3]

Answer 4

map将函数应用于iterable中的每个元素，并将其作为新列表返回。在这种情况下，您可以使用str.strip删除字符串两端的空格。

myList = ['41.6640', '-91.5447\n', '41.6640', '-91.5447\n', '41.6640', '-91.5447\n', '41.6640', '-91.5447\n', '41.6640', '-91.5447\n']
myList = map(str.strip, myList)

Python解析和清理

4 个答案: