我在Metal中结合Swift实现多核函数时遇到了问题。
我的目标是在图像上实现逐块DCT变换。 DCT通过两次矩阵乘法实现。
J = H * I * H ^ -1
以下代码显示了内核函数本身以及swift代码中使用的调用。如果我单独运行每个内核函数它可以工作,但我无法设法将写入缓冲区从第一个内核函数移交给第二个函数。因此,第二个函数总是返回一个只填充0的缓冲区。
所有图像输入和输出缓冲区都是400x400大的RGB(每个组件16位整数)。矩阵是8x8 16位整数。
是否需要一个特殊的命令来同步不同内核函数的缓冲区读写访问?或者我做错了什么?
感谢您的帮助
shaders.metal
struct Image3D16{
short data[400][400][3];
};
struct Matrix{
short data[8 * 8];
};
kernel void dct1(device Image3D16 *inputImage [[buffer(0)]],
device Image3D16 *outputImage [[buffer(1)]],
device Matrix *mult [[buffer(2)]],
uint2 gid [[thread_position_in_grid]],
uint2 tid [[thread_position_in_threadgroup]]){
int red = 0, green = 0, blue = 0;
for(int x=0;x<8;x++){
short r = inputImage->data[gid.x-tid.x + x][gid.y][0];
short g = inputImage->data[gid.x-tid.x + x][gid.y][1];
short b = inputImage->data[gid.x-tid.x + x][gid.y][2];
red += r * mult->data[tid.x*8 + x];
green += g * mult->data[tid.x*8 + x];
blue += b * mult->data[tid.x*8 + x];
}
outputImage->data[gid.x][gid.y][0] = red;
outputImage->data[gid.x][gid.y][1] = green;
outputImage->data[gid.x][gid.y][2] = blue;
}
kernel void dct2(device Image3D16 *inputImage [[buffer(0)]],
device Image3D16 *outputImage [[buffer(1)]],
device Matrix *mult [[buffer(2)]],
uint2 gid [[thread_position_in_grid]],
uint2 tid [[thread_position_in_threadgroup]]){
int red = 0, green = 0, blue = 0;
for(int y=0;y<8;y++){
short r = inputImage->data[gid.x][gid.y-tid.y + y][0];
short g = inputImage->data[gid.x][gid.y-tid.y + y][1];
short b = inputImage->data[gid.x][gid.y-tid.y + y][2];
red += r * mult->data[tid.y*8 + y];
green += g * mult->data[tid.y*8 + y];
blue += b * mult->data[tid.y*8 + y];
}
outputImage->data[gid.x][gid.y][0] = red;
outputImage->data[gid.x][gid.y][1] = green;
outputImage->data[gid.x][gid.y][2] = blue;
}
ViewController.swift
...
let commandBuffer = commandQueue.commandBuffer()
let computeEncoder1 = commandBuffer.computeCommandEncoder()
computeEncoder1.setComputePipelineState(computeDCT1)
computeEncoder1.setBuffer(input, offset: 0, atIndex: 0)
computeEncoder1.setBuffer(tmpBuffer3D1, offset: 0, atIndex: 1)
computeEncoder1.setBuffer(dctMatrix1, offset: 0, atIndex: 2)
computeEncoder1.dispatchThreadgroups(blocks, threadsPerThreadgroup: dctSize)
computeEncoder1.endEncoding()
let computeEncoder2 = commandBuffer.computeCommandEncoder()
computeEncoder2.setComputePipelineState(computeDCT2)
computeEncoder2.setBuffer(tmpBuffer3D1, offset: 0, atIndex: 0)
computeEncoder2.setBuffer(output, offset: 0, atIndex: 1)
computeEncoder2.setBuffer(dctMatrix2, offset: 0, atIndex: 2)
computeEncoder2.dispatchThreadgroups(blocks, threadsPerThreadgroup: dctSize)
computeEncoder2.endEncoding()
commandBuffer.commit()
commandBuffer.waitUntilCompleted()
答案 0 :(得分:4)
我发现了错误。我的内核函数试图在其分配的内存之外读取。然后,金属接口的反应是停止在命令缓冲区中执行所有后续命令。因此,输出始终为零,因为计算从未完成。应用程序的GPU使用率下降,可用于检测错误。