使用现有代码在PHP中生成随机数

Question

我正在使用以下代码并获得6个随机字符。如何将字符数增加到10（或任何其他数字）？这段代码中的内容是6个字符？

function createRandomID() {

$chars = "abcdefghijkmnopqrstuvwxyz0123456789?";

$i = 0;

$pass = "";

while ($i <= 5) {

$num = rand() % 33;

$tmp = substr($chars, $num, 1);

$pass = $pass . $tmp;

$i++;

}
return $pass;
}

Answer 1

您已经得到了正确的答案，因此您的代码变为：

function createRandomID() {

$chars = "abcdefghijkmnopqrstuvwxyz0123456789?";

$i = 0;

$pass = "";

$upTo = 9 // if you want 10 or whatever - 1

while ($i <= $upTo) {

$num = rand() % 33;

$tmp = substr($chars, $num, 1);

$pass = $pass . $tmp;

$i++;

}
return $pass;
}