我试图从一组数字中显示10个随机数,但没有成功。
这是我的代码:
<?php
$num = array("2000", "2001", "2002", "2003", "2004", "2005", "2006", "2007", "2008", "2009");
//echo $num[rand(0,9)];
echo '<br/>';
for ($num = 2000; $num <= 10; $num[rand(0,9)]++)
{
echo "The number is " . $num . "<br />";
}
?>
虽然我的ubuntu php.ini上有display_errors = On
,但脚本没有显示任何内容。
我哪里错了?
答案 0 :(得分:3)
只需使用array_rand
:
array_rand($num, 10); // returns a new array with 10 randomly selected values.
之后,您可以使用foreach
$rand = array_rand($num, 10);
foreach($rand as $key) {
echo "The number is " . $num[key] . "<br />";
}
答案 1 :(得分:3)
我会改用shuffle
函数。
<?php
$num = array("2000", "2001", "2002", "2003", "2004", "2005", "2006", "2007", "2008", "2009");
shuffle($num);
echo '<br/>';
foreach ($num as $value)
{
echo "The number is " . $value . "<br />";
}
?>
答案 2 :(得分:1)
$num= array("2000", "2001", "2002", "2003", "2004", "2005", "2006", "2007", "2008",
"2009");
shuffle($num);
//echo $num[rand(0,9)];
echo '<br/>';
for ($i = 0; $i < count($num); $i++)
{
echo "The number is " . $num[$i] . "<br />";
}
答案 3 :(得分:0)
您从$num = 2000
开始循环,并在$num <= 10
时停止。所以它没有执行。
答案 4 :(得分:0)
<?php
$num= array("2000", "2001", "2002", "2003", "2004", "2005", "2006", "2007", "2008",
"2009");
//echo $num[rand(0,9)];
echo '<br/>';
for ($i = 0; $i < count($num); $i++)
{
echo "The number is " . $num[rand(0, count($num))] . "<br />";
}
?>
答案 5 :(得分:0)
$num= array("2000", "2001", "2002", "2003", "2004", "2005", "2006", "2007", "2008", "2009");
for($i=0; $i<10; $i++){
$rand = rand(0,count($num));
echo "The number is " . $num[$rand] . "<br />";
// unset($num[$rand]); //to get unique numbers each time .. this will unset array item after its showed
// $num = array_values($num); //reindex after unset
}
如果您只想获得唯一结果,可以使用unset和array_values