在android浓咖啡检查吐司消息

时间：2015-02-08 04:28:54

标签： android android-espresso toast

有人知道如何在android espresso中测试Toast消息的外观吗？在机器人中，它简单易用。我曾经使用但开始使用浓缩咖啡，但没有得到确切的命令。

14 个答案:

答案 0 :(得分：102)

这个稍长的陈述对我有用：

import static android.support.test.espresso.assertion.ViewAssertions.matches;
import static android.support.test.espresso.matcher.RootMatchers.withDecorView;
import static android.support.test.espresso.matcher.ViewMatchers.isDisplayed;
import static android.support.test.espresso.matcher.ViewMatchers.withText;
import static org.hamcrest.Matchers.is;
import static org.hamcrest.Matchers.not;
....
onView(withText(R.string.TOAST_STRING)).inRoot(withDecorView(not(is(getActivity().getWindow().getDecorView())))).check(matches(isDisplayed()));

答案 1 :(得分：41)

接受的答案是好的，但对我没有用。所以我搜索了一下，发现了this blog article。 这让我知道如何做到这一点，并更新了上面的解决方案。

首先我实现了Toa​​stMatcher：

import android.os.IBinder;
import android.support.test.espresso.Root;
import android.view.WindowManager;
import org.hamcrest.Description;
import org.hamcrest.TypeSafeMatcher;

public class ToastMatcher extends TypeSafeMatcher<Root> {

  @Override
  public void describeTo(Description description) {
    description.appendText("is toast");
  }

  @Override
  public boolean matchesSafely(Root root) {
    int type = root.getWindowLayoutParams().get().type;
    if (type == WindowManager.LayoutParams.TYPE_TOAST) {
        IBinder windowToken = root.getDecorView().getWindowToken();
        IBinder appToken = root.getDecorView().getApplicationWindowToken();
        if (windowToken == appToken) {
            // windowToken == appToken means this window isn't contained by any other windows.
            // if it was a window for an activity, it would have TYPE_BASE_APPLICATION.
            return true;
        }
    }
    return false;
  }

}

然后我实现了我的检查方法：

public void isToastMessageDisplayed(int textId) {
    onView(withText(textId)).inRoot(MobileViewMatchers.isToast()).check(matches(isDisplayed()));
}

MobileViewMatchers是一个用于访问匹配器的容器。我在那里定义了静态方法isToast()。

public static Matcher<Root> isToast() {
    return new ToastMatcher();
}

这对我来说就像是一种魅力。

答案 2 :(得分：11)

首先确保导入：

import static android.support.test.espresso.Espresso.onView;
import static android.support.test.espresso.matcher.ViewMatchers.withText;
import static android.support.test.espresso.matcher.RootMatchers.withDecorView;
import static android.support.test.espresso.assertion.ViewAssertions.matches;

在课堂上你可能有这样的规则：

@Rule
public ActivityTestRule<MyNameActivity> activityTestRule =
            new ActivityTestRule<>(MyNameActivity.class);

在测试中：

MyNameActivity activity = activityTestRule.getActivity();
onView(withText(R.string.toast_text)).
    inRoot(withDecorView(not(is(activity.getWindow().getDecorView())))).
    check(matches(isDisplayed()));

这对我有用，而且很容易使用。

答案 3 :(得分：3)

虽然这个问题有一个公认的答案--BTW对我不起作用 - 我想在Kotlin中添加我的解决方案，这是我从Thomas R.的答案中得出的：

package somepkg

import android.support.test.espresso.Espresso.onView
import android.support.test.espresso.Root
import android.support.test.espresso.matcher.ViewMatchers.withText
import android.view.WindowManager.LayoutParams.TYPE_APPLICATION_OVERLAY
import android.view.WindowManager.LayoutParams.TYPE_TOAST
import org.hamcrest.Description
import org.hamcrest.Matcher
import org.hamcrest.TypeSafeMatcher

/**
 * This class allows to match Toast messages in tests with Espresso.
 *
 * Idea taken from: https://stackoverflow.com/a/33387980
 *
 * Usage in test class:
 *
 * import somepkg.ToastMatcher.Companion.onToast
 *
 * // To assert a toast does *not* pop up:
 * onToast("text").check(doesNotExist())
 * onToast(textId).check(doesNotExist())
 *
 * // To assert a toast does pop up:
 * onToast("text").check(matches(isDisplayed()))
 * onToast(textId).check(matches(isDisplayed()))
 */
class ToastMatcher(private val maxFailures: Int = DEFAULT_MAX_FAILURES) : TypeSafeMatcher<Root>() {

    /** Restrict number of false results from matchesSafely to avoid endless loop */
    private var failures = 0

    override fun describeTo(description: Description) {
        description.appendText("is toast")
    }

    public override fun matchesSafely(root: Root): Boolean {
        val type = root.windowLayoutParams.get().type
        @Suppress("DEPRECATION") // TYPE_TOAST is deprecated in favor of TYPE_APPLICATION_OVERLAY
        if (type == TYPE_TOAST || type == TYPE_APPLICATION_OVERLAY) {
            val windowToken = root.decorView.windowToken
            val appToken = root.decorView.applicationWindowToken
            if (windowToken === appToken) {
                // windowToken == appToken means this window isn't contained by any other windows.
                // if it was a window for an activity, it would have TYPE_BASE_APPLICATION.
                return true
            }
        }
        // Method is called again if false is returned which is useful because a toast may take some time to pop up. But for
        // obvious reasons an infinite wait isn't of help. So false is only returned as often as maxFailures specifies.
        return (++failures >= maxFailures)
    }

    companion object {

        /** Default for maximum number of retries to wait for the toast to pop up */
        private const val DEFAULT_MAX_FAILURES = 5

        fun onToast(text: String, maxRetries: Int = DEFAULT_MAX_FAILURES) = onView(withText(text)).inRoot(isToast(maxRetries))!!

        fun onToast(textId: Int, maxRetries: Int = DEFAULT_MAX_FAILURES) = onView(withText(textId)).inRoot(isToast(maxRetries))!!

        fun isToast(maxRetries: Int = DEFAULT_MAX_FAILURES): Matcher<Root> {
            return ToastMatcher(maxRetries)
        }
    }

}

我希望这对后来的读者有所帮助 - 评论中描述了这种用法。

答案 4 :(得分：2)

首先创建一个cutom Toast Matcher，我们可以在我们的测试用例中使用它 - 

public class ToastMatcher extends TypeSafeMatcher<Root> {

    @Override    public void describeTo(Description description) {
        description.appendText("is toast");
    }

    @Override    public boolean matchesSafely(Root root) {
        int type = root.getWindowLayoutParams().get().type;
        if ((type == WindowManager.LayoutParams.TYPE_TOAST)) {
            IBinder windowToken = root.getDecorView().getWindowToken();
            IBinder appToken = root.getDecorView().getApplicationWindowToken();
            if (windowToken == appToken) {
              //means this window isn't contained by any other windows. 
            }
        }
        return false;
    }

<强> 1。测试是否显示Toast消息 

onView(withText(R.string.mssage)).inRoot(new ToastMatcher())
.check(matches(isDisplayed()));

<强> 2。测试是否未显示Toast消息 

onView(withText(R.string.mssage)).inRoot(new ToastMatcher())
.check(matches(not(isDisplayed())));

第3。测试ID Toast包含特定的文本消息 

onView(withText(R.string.mssage)).inRoot(new ToastMatcher())
.check(matches(withText("Invalid Name"));

谢谢， Anuja

注意 - 此答案来自This POST.

答案 5 :(得分：0)

我想为吐司消息先定义您的规则

 @Rule
   public ActivityTestRule<AuthActivity> activityTestRule =
   new ActivityTestRule<>(AuthActivity.class);

然后，您要查找的任何吐司消息文本都在引号之间键入        例如我使用了“无效的电子邮件地址” 

   onView(withText("Invalid email address"))
    .inRoot(withDecorView(not(activityTestRule.getActivity().getWindow().getDecorView())))
    .check(matches(isDisplayed()));

答案 6 :(得分：0)

如果您使用的是来自 Jetpack 的最新 Android测试工具，那么您知道ActivityTestRule已过时，您应该使用ActivityScenario或ActivityScenarioRule（其中包含第一个）

先决条件。创建decorView变量并在测试之前分配它； 

    @Rule
    public ActivityScenarioRule<FeedActivity> activityScenarioRule = new ActivityScenarioRule<>(FeedActivity.class);

    private View decorView;

    @Before
    public void setUp() {
        activityScenarioRule.getScenario().onActivity(new ActivityScenario.ActivityAction<FeedActivity>() {
            @Override
            public void perform(FeedActivityactivity) {
                decorView = activity.getWindow().getDecorView();
            }
        });
}

测试自己

@Test
public void given_when_thenShouldShowToast() {
    String expectedWarning = getApplicationContext().getString(R.string.error_empty_list);
    onView(withId(R.id.button))
            .perform(click());

    onView(withText(expectedWarning))
            .inRoot(withDecorView(not(decorView)))// Here we use decorView
            .check(matches(isDisplayed()));
}

getApplicationContext（）可以从androidx.test.core.app.ApplicationProvider.getApplicationContext;

中获取

答案 7 :(得分：0)

我写了我的自定义吐司匹配器：

import android.view.WindowManager
import androidx.test.espresso.Root
import org.hamcrest.Description;
import org.hamcrest.TypeSafeMatcher;
class ToastMatcher : TypeSafeMatcher<Root>() {

    override fun describeTo(description: Description) {
        description.appendText("is toast")
    }

    override fun matchesSafely(root: Root): Boolean {
        val type = root.getWindowLayoutParams().get().type
        if (type == WindowManager.LayoutParams.TYPE_TOAST) {
            val windowToken = root.getDecorView().getWindowToken()
            val appToken = root.getDecorView().getApplicationWindowToken()
            if (windowToken === appToken) {
                return true
            }
        }
        return false
    }
}

并像这样使用：

onView(withText(R.string.please_input_all_fields)).inRoot(ToastMatcher()).check(matches(isDisplayed()))

答案 8 :(得分：0)

我对此很陌生，但是我创建了一个基类“ BaseTest”，其中包含我的所有操作（滑动，单击等）和验证（检查文本视图中的内容等）。

{{1}}

答案 9 :(得分：0)

这对我有用

onView（withId（R.id.inputField））。check（matches（withText（“ Lalala”））））;

答案 10 :(得分：0)

我想建议一种替代方法，特别是如果您需要检查是否显示了不的特定吐司

这里的问题

|

或

onView(viewMatcher)
    .inRoot(RootMatchers.isPlatformPopup())
    .check(matches(not(isDisplayed())))

或任何其他自定义onView(viewMatcher) .inRoot(RootMatchers.isPlatformPopup()) .check(doesNotExist()) 检查 在代码传递给inRoot方法之前就抛出了NoMatchingRootException

您可能只捕获了异常并完成了测试，但这不是一个好选择，因为与默认测试用例相比，抛出和捕获check会花费大量时间。似乎意式浓缩咖啡正在等待Root一段时间

对于这种情况，建议仅在此处放弃浓缩咖啡，并使用NoMatchingRootException进行此声明。 UiAutomator和Espresso框架可以轻松地在一个环境中协同工作。

UiAutomator

答案 11 :(得分：0)

对于Kotlin，我必须使用Apply扩展功能，这对我来说很有效。

1-在androidTest文件夹中声明您的ToastMatcher类：

class ToastMatcher : TypeSafeMatcher<Root?>() {

override fun matchesSafely(item: Root?): Boolean {
        val type: Int? = item?.windowLayoutParams?.get()?.type
        if (type == WindowManager.LayoutParams.FIRST_APPLICATION_WINDOW) {
            val windowToken: IBinder = item.decorView.windowToken
            val appToken: IBinder = item.decorView.applicationWindowToken
            if (windowToken === appToken) { // means this window isn't contained by any other windows.
                return true
            }
        }
        return false
    }

    override fun describeTo(description: Description?) {
        description?.appendText("is toast")
    }
}

2-然后您可以像这样测试吐司消息是否真正显示

onView(withText(R.string.invalid_phone_number))
        .inRoot(ToastMatcher().apply {
            matches(isDisplayed())
        });

ToastMatcher类的归属：

/**
 * Author: http://www.qaautomated.com/2016/01/how-to-test-toast-message-using-espresso.html
 */

答案 12 :(得分：0)

使用ActivityScenarioRule和Java

一些导入代码

import android.view.View;
import androidx.test.ext.junit.rules.ActivityScenarioRule;

import org.junit.Before;
import org.junit.Rule;
import org.junit.Test;

import static androidx.test.espresso.Espresso.onView;
import static androidx.test.espresso.matcher.RootMatchers.withDecorView;
import static androidx.test.espresso.matcher.ViewMatchers.isDisplayed;
import static androidx.test.espresso.matcher.ViewMatchers.withId;
import static androidx.test.espresso.matcher.ViewMatchers.withText;
import static org.hamcrest.Matchers.not;

1。声明规则 

//Change YourActivity by the activity you are testing
@Rule
public ActivityScenarioRule<YourActivity> activityRule
        = new ActivityScenarioRule<>(YourActivity.class);

2。初始化装饰视图 

    private View decorView;

    @Before
    public void loadDecorView() {
        activityRule.getScenario().onActivity(
                activity -> decorView = activity.getWindow().getDecorView()
        );
    }

3。最后测试 

    @Test
    public void testWithToasts() {


        //Arrange and act code

        //Modify toast_msg to your own string resource
        onView(withText(R.string.toast_msg)).
                inRoot(RootMatchers.withDecorView(not(decorView)))
                .check(matches(isDisplayed()));
    }

答案 13 :(得分：-3)

实现Toasts的方式可以检测已显示的Toast。然而，无法通过调用show（）来查看是否已经请求了Toast，或者在show（）和toast可见之间的时间段之间阻止了Toast。这会打开无法解决的时间问题（你只能通过睡眠和希望来解决）。

如果你真的想要验证这一点，那么使用Mockito和测试间谍是一个不那么漂亮的选择：

public interface Toaster {
 public void showToast(Toast t);

 private static class RealToaster {
  @Override
  public void showToast(Toast t) {
    t.show();
  }

 public static Toaster makeToaster() {
   return new RealToaster();
 }
}

Then in your test

public void testMyThing() {
 Toaster spyToaster = Mockito.spy(Toaster.makeToaster());
 getActivity().setToaster(spyToaster);
 onView(withId(R.button)).perform(click());
 getInstrumentation().runOnMainSync(new Runnable() {
 @Override
  public void run() {
   // must do this on the main thread because the matcher will be interrogating a view...
   Mockito.verify(spyToaster).showToast(allOf(withDuration(Toast.LENGTH_SHORT), withView(withText("hello world"));
 });
}

// create a matcher that calls getDuration() on the toast object
Matcher<Toast> withDuration(int)
// create a matcher that calls getView() and applies the given view matcher
Matcher<Toast> withView(Matcher<View> viewMatcher)




another answer regarding this 




if(someToast == null)
    someToast = Toast.makeText(this, "sdfdsf", Toast.LENGTH_LONG);
boolean isShown = someToast.getView().isShown();
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