Question

我正在学习python编程并且遇到了这个问题。我查看了其他示例，它们读取文件输入并将整个事件作为单个列表或字符串link to that example但我希望每行都是是一个列表（嵌套列表）我该怎么做请帮助
文本文件是a.txt

1234 456 789 10 11 12 13

4456 585 568 2 11 13 15

代码的输出必须像这样

[ [1234 456 789 10 11 12 13],[4456 585 568 2 11 13 15] ]

Answer 1

没理由readlines - 只是遍历文件。

with open('path/to/file.txt') as f:
    result = [line.split() for line in f]

如果您想要一个整体列表列表：

with open('path/to/file.txt') as f:
    result = [map(int, line.split()) for line in f]
    # [list(map(int, line.split())) for line in f] in Python3

Answer 2

你可以做到

with open('a.txt') as f:
     [[i.strip()] for i in f.readlines()]

会打印

[['1234 456 789 10 11 12 13'], ['4456 585 568 2 11 13 15']]

注意 - 这是打印字符串的初始问题的答案

要完全按照您的意愿打印而不加引号，这是一个非常错误的方法

print(repr([[i.strip()] for i in f.readlines()]).replace("'",''))

将打印

[[1234 456 789 10 11 12 13], [4456 585 568 2 11 13 15]]

Answer 3

lines = open('file.txt').readlines() # parse file by lines
lines = [i.strip().split(' ') for i in lines] # remove newlines, split spaces
lines = [[int(i) for i in j] for j in lines] # cast to integers

Answer 4

在结果列表中看起来你想要整数，而不是字符串;如果是的话：

with open(filename) as f:
    result = [[int(x) for x in line.strip().split()] for line in f]

如何在python中将文件的内容写入列表？

4 个答案: