Question

所以我有这样的数据

id    type    date
1      1      2015-02-04
2      1      2015-02-04
3      2      2015-02-04
4      1      2015-02-05
5      2      2015-02-06

我想要一个像这样的结果

countForType1    countForType2      dow
      2               1           Wednesday
      1               0           Thursday
      0               1            Friday
etc...

我尝试使用OVER(PARTITION，但我认为我使用不正确，或者可能，我需要使用其他内容。这是我目前的查询：

SELECT 
    COUNT(seatType) OVER(PARTITION BY seatType) AS Counts,
    CASE DATEPART(DW,testDate)
        WHEN 1 THEN 'Sunday'
        WHEN 2 THEN 'Monday'
        WHEN 3 THEN 'Tuesday'
        WHEN 4 THEN 'Wednesday'
        WHEN 5 THEN 'Thursday'
        WHEN 6 THEN 'Friday'
        WHEN 7 THEN 'Saturday'
    END dow
FROM tst_Tests
WHERE roomid = 1
GROUP BY DATEPART(DW,testDate), seatType

我不确定如何根据各个座位类型创建第二列。我想我可以在select语句中放入两个select语句，但这似乎效率低下。我觉得有一个功能，我使用不正确或根本没有。

编辑：我让示例数据与实际日期和返回的数字相匹配。

Answer 1

您应该使用Conditional Aggergate代替window function

SELECT Count(CASE WHEN type = 1 THEN 1 END) AS countForType1,
       Count(CASE WHEN type = 2 THEN 1 END) AS countForType2,
       CASE
         WHEN Datepart(DW, date) = 1 THEN 'Sunday'
         WHEN Datepart(DW, date) = 2 THEN 'Monday'
         WHEN Datepart(DW, date) = 3 THEN 'Tuesday'
         WHEN Datepart(DW, date) = 4 THEN 'Wednesday'
         WHEN Datepart(DW, date) = 5 THEN 'Thursday'
         WHEN Datepart(DW, date) = 6 THEN 'Friday'
         WHEN Datepart(DW, date) = 7 THEN 'Saturday'
       END        dow
FROM   Yoursampletable
GROUP  BY Datepart(DW, date)

Answer 2

喜欢这个吗？

DECLARE @Example TABLE ([Id] int, [type] int, [testDate] date)

INSERT INTO @Example ([Id], [type], [testDate])
SELECT 1,1,'2015-02-04' UNION ALL
SELECT 2,1,'2015-02-04' UNION ALL
SELECT 3,2,'2015-02-04' UNION ALL
SELECT 4,1,'2015-02-05' UNION ALL
SELECT 5,2,'2015-02-06'

;with rowsWithDayName as (
  select *, 
      CASE WHEN DATEPART(DW,testDate) = 1 THEN 'Sunday'
      WHEN DATEPART(DW,testDate) = 2 THEN 'Monday'
      WHEN DATEPART(DW,testDate) = 3 THEN 'Tuesday'
      WHEN DATEPART(DW,testDate) = 4 THEN 'Wednesday'
      WHEN DATEPART(DW,testDate) = 5 THEN 'Thursday'
      WHEN DATEPART(DW,testDate) = 6 THEN 'Friday'
      WHEN DATEPART(DW,testDate) = 7 THEN 'Saturday'
  END as [DayName]
  from @Example
)
select 
SUM(CASE WHEN [type]=1 THEN 1 ELSE 0 END) as countForType1
, SUM(CASE WHEN [type]=2 THEN 1 ELSE 0 END) as countForType2
, [DayName]
FROM rowsWithDayName
group by [DayName]

SQL - 同一行上的组结果

2 个答案: