Question

我创建了一个名为tbl_timesheet_hours的数据库表，如下所示：

timesheet_no
work_order_no
work_order_date
work_order_hours

表中填充的数据为：

timesheet_no    work_order_no   work_order_date     work_order_hours
4               NTS0026B        2012-01-02          1
4               NTS0031B        2012-01-02          9
4               NTS0031B        2012-01-03          8
4               NTS0031B        2012-01-04          7
4               NTS0031B        2012-01-05          6
4               NTS0031B        2012-01-06          5
4               NTS0031B        2012-01-07          4
4               NTS0031B        2012-01-08          3

我需要创建一个查询，该查询将形成时间表报告的基础，该报告可以以典型的承包商的时间表格式打印，即，它将在第一列中显示work_order_no字段，然后为每个分配显示小时数天。我创建的查询是：

SELECT
  work_order_no,
  switch(Format(work_order_date,'ddd') = "Mon", SUM(work_order_hours)) AS [Mon],
  switch(Format(work_order_date,'ddd') = "Tue", SUM(work_order_hours)) AS [Tue],
  switch(Format(work_order_date,'ddd') = "Wed", SUM(work_order_hours)) AS [Wed],
  switch(Format(work_order_date,'ddd') = "Thu", SUM(work_order_hours)) AS [Thu],
  switch(Format(work_order_date,'ddd') = "Fri", SUM(work_order_hours)) AS [Fri],
  switch(Format(work_order_date,'ddd') = "Sat", SUM(work_order_hours)) AS [Sat],
  switch(Format(work_order_date,'ddd') = "Sun", SUM(work_order_hours)) AS [Sun]
FROM tbl_timesheet_hours
WHERE timesheet_no=4
GROUP BY work_order_date, work_order_no;

查询生成以下结果集

work_order_no   Mon Tue Wed Thu Fri Sat Sun
NTS0026B         1                      
NTS0031B         9                      
NTS0031B             8                  
NTS0031B                 7              
NTS0031B                     6          
NTS0031B                         5      
NTS0031B                             4  
NTS0031B                                 3

是否可以重构查询以生成以下结果集？

work_order_no   Mon Tue Wed Thu Fri Sat Sun
NTS0026B        1                       
NTS0031B        9   8   7   6   5   4   3

非常感谢任何类型的协助。感谢。

Answer 1

您可以按如下方式使用交叉表查询：

TRANSFORM Sum(tbl_timesheet_hours.[work_order_hours]) AS SumOfwork_order_hours
SELECT tbl_timesheet_hours.[work_order_no], Sum(tbl_timesheet_hours.[work_order_hours]) AS     [Total Of work_order_hours]
FROM tbl_timesheet_hours
GROUP BY tbl_timesheet_hours.[work_order_no]
ORDER BY Format([work_order_date],'ddd')
PIVOT Format([work_order_date],'ddd') In ("Mon","Tue","Wed","Thu","Fri","Sat","Sun");

Answer 2

您是否尝试过使用 SWITCH内的SUM()表达式？像这样：

SELECT work_order_no, SUM(switch(Format(work_order_date,'ddd') = "Mon", work_order_hours)) AS [Mon], SUM(switch(Format(work_order_date,'ddd') = "Tue", work_order_hours)) AS [Tue], SUM(switch(Format(work_order_date,'ddd') = "Wed", work_order_hours)) AS [Wed], SUM(switch(Format(work_order_date,'ddd') = "Thu", work_order_hours)) AS [Thu], SUM(switch(Format(work_order_date,'ddd') = "Fri", work_order_hours)) AS [Fri], SUM(switch(Format(work_order_date,'ddd') = "Sat", work_order_hours)) AS [Sat], SUM(switch(Format(work_order_date,'ddd') = "Sun", work_order_hours)) AS [Sun] FROM tbl_timesheet_hours WHERE timesheet_no=4 GROUP BY work_order_no;

除此之外，还要从work_order_date移除GROUP BY。

Group By SQL Statement - 将结果合并到一行

2 个答案: