Question

我想知道如何对行进行分组查询，这是一个更好地解释它的例子。

Column1 Column2 Column3
AD                2
AD        AD      79
AD        ES      2
AD        US      2

我想要这个结果：

Column1 Column2     Column3
AD        AD          79
AD        NOT EQUAL   6

提前致谢...我正在尝试处理案件，但却取得了成功。

  SELECT UPPER(Column1), UPPER(Column2), COUNT(*) FROM MyTable
  GROUP BY UPPER(Column1), UPPER(Column2)
  HAVING UPPER(Column1) = UPPER(Column2)
  ORDER BY UPPER(Column1) ASC

QUERY

  SELECT UPPER(FirstCode), UPPER(SecondCode), COUNT(*) FROM [EducaWorkSpace].[dbo].[tblIPCountry] 
  GROUP BY UPPER(FirstCode), UPPER(SecondCode)
  ORDER BY UPPER(FirstCode) ASC


  SELECT P.FirstCode as PaisCodeC, CASE WHEN P.FirstCode<>ISNULL(P.SecondCode, '') THEN 'NOT EQUAL' ELSE P.SecondCode END AS PaisCodeIPC, SUM(Cantidad) as CantidadC
  FROM
  (
  SELECT UPPER(FirstCode) FirstCode, UPPER(SecondCode) SecondCode, COUNT(*) Cantidad FROM [dbo].[tblCodes] 
  GROUP BY UPPER(FirstCode), UPPER(SecondCode)
  ) P
  Group BY P.FirstCode, CASE WHEN P.SecondCode<>ISNULL(P.SecondCode, '') THEN 'Not Equal' ELSE P.SecondCode END

Answer 1

在这里，试试这个：

SELECT Column1, 
    CASE WHEN Column1<>ISNULL(Column2, '') 
    THEN 'Not Equal' 
    ELSE Column2 END AS Column2, 
    SUM(Column3)
FROM MyTable
GROUP BY Column1, 
    CASE WHEN Column1<>ISNULL(Column2, '') 
    THEN 'Not Equal' 
    ELSE Column2 END

SQL Server分组查询

1 个答案: