Question

我有一个由12列组成的表，如下所示：

acct, addr1, addr2, addr3, addr4, addr5, 
addr6, addr7, add8, zip, domicile, shares

我需要的是将总shares汇总到一行以获得重复的行。标准是addr1到addr4是相同的，它确定该行是重复的。

我尝试了这个，但它没有用。

SELECT acct, addr1, addr2, addr3, addr4, addr5, 
addr6, addr7, add8, 
       zip, DOMICILE, sum(shares) as total_shares 
FROM table_name 
GROUP BY addr1, addr2, addr3, addr4 ORDER BY addr1;

Answer 1

您正在选择不在GROUP BY子句中的列。您必须对它们进行一些修改才能将它们放入结果集中，通常使用MIN或MAX，例如：

SELECT MIN(acct) as acct, na1, na2, na3, na4, MIN(na5) as na5, MIN(na6) as na6, MIN(na7) as na7, MIN(na8) as na8, MIN(zip) as zip, MIN(DOMICILE) as DOMICILE, sum(shares) as total_shares
FROM table_name
GROUP BY na1, na2, na3, na4
ORDER BY na1

Answer 2

尝试做一些表格gropuping逻辑，如INTERSECT或EXCEPT

您可以根据需要组合不同的列...

在这个例子中，我将捕获所有的情况（addr1 = addr2 = addr3 = addr4）

SELECT acct, addr1 FROM table_name 
INTERSECT
SELECT acct, addr2 FROM table_name 
INTERSECT
SELECT acct, addr3 FROM table_name 
INTERSECT
SELECT acct, addr4 FROM table_name

Answer 3

select sum(total_shares)
from 
(
  SELECT na1, na2, na3, na4, sum(shares) as total_shares 
    FROM table_name 
   GROUP BY na1, na2, na3, na4 
  having count(*) > 1
) ttl

使用分组查询

3 个答案: