Question

我有ArrayList<ArrayList<String>>个数据列表。我想通过多个字段对列表进行排序。如果我知道排序字段的数量，我没有问题。例如，如果我想按字段排序，其索引位于此位置（3,2,5）。示例在此处：

public int compare(List<String> rowData1, List<String> rowData2) {
    String[] arr = { "2", "3", "4", "1" };
        String s1 = rowData1.get(Integer.parseInt(arr[0]));
            String s2 = rowData2.get(Integer.parseInt(arr[0]));
            int comp = s1.compareTo(s2);
            if (comp != 0) {
                result = comp;

            } else {

                String z1 = rowData1.get(Integer.parseInt(arr[1]));
                String z2 = rowData2.get(Integer.parseInt(arr[1]));
                int comp1 = z1.compareTo(z2);
                if (comp1 != 0) {
                    result = comp1;
                } else {

                    String c1 = rowData1.get(Integer.parseInt(arr[2]));
                    String c2 = rowData2.get(Integer.parseInt(arr[2]));
                    int comp2 = c1.compareTo(c2);
                    if (comp2 != 0) {
                        result = comp2;
                    } else {
                        String b1 = rowData1.get(Integer.parseInt(arr[3]));
                        String b2 = rowData2.get(Integer.parseInt(arr[3]));
                        result = b1.compareTo(b2);
                    }
                }
            }
}

我想拥有动态（可配置）数组。等待你的建议。

Answer 1

我的意思是这样的：

public class Cumpare implements Comparator<List<String>> {

private final int[] indexes;

public Cumpare(final int[] indexes) {
    this.indexes = indexes;
}


@Override
public int compare(final List<String> o1, final List<String> o2) {
    int value = 0;
    for(int i : indexes){
        value = o1.get(i).compareTo(o2.get(i));
        if (value!=0) break;                        
    }
    return value;
}
}

Java Comparator按多个字段排序，字段数应该是动态的

1 个答案: