Question

我尝试使用以下方法允许自己在我的控制台应用程序中输入极大值，例如10^15000。此应用程序必须计算足够大的值，以便使用Stopwatch对象进行计时，并在1秒内降落。到目前为止，我只能在使用Console.SetIn(new StreamReader(Console.OpenStandardInput(8192)));

时获得允许的最大输入字符数

这是我的自定义ReadLine（）方法：

static string ReadLine()
{
    StringBuilder sb = new StringBuilder();
    while(true){
        char ch = Convert.ToChar(Console.Read());
        sb.Append(ch);
        if(ch == '\n'){
            break;
        }
    }

    return sb.ToString();
}

这是我的整个程序，专门用于算法时间测试：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Numerics;
using System.Diagnostics;
using System.IO;

namespace LabGrowthOfFunctions
{
    class Program
    {        
        static void Main(string[] args)
        {
            int userNum;

            Console.Write("Please enter a number: ");
            Console.SetIn(new StreamReader(Console.OpenStandardInput(8192))); 

            string tempString = ReadLine();  
            int.TryParse(tempString, out userNum);

            Stopwatch sw = Stopwatch.StartNew();
            //nsquaredgrowthversion1(userNum);
            //ncubedfunction(userNum);
            ntothefourthpowerfunction(userNum);
            //nfunction(userNum);
            //nlognfunction(userNum);
            sw.Stop();

            Console.WriteLine("Time used: {0} secs", sw.Elapsed.TotalMilliseconds / 1000);
            Console.ReadLine();
        }

        private static void nsquaredgrowthversion1(int n)
        {
            int sum = 0;
            for (int i = 0; i < n; i++)
                for (int j = 0; j < n; j++)
                    sum++;
        }

        private static void ncubedfunction(int n)
        {
            int sum = 0;
            for (int i = 0; i < n; i++)
                for (int j = 0; j < n; j++)
                    for (int k = 0; k < n; k++)
                        sum++;
        }

        private static void ntothefourthpowerfunction(int n)
        {
            int sum = 0;
            for (int i = 0; i < n; i++)
                for (int j = 0; j < n; j++)
                    for (int k = 0; k < n; k++)
                        for (int l = 0; l < n; l++)
                            sum++;
        }

        private static void nfunction(int n)
        {
            int sum = 0;

            for (int i = 0; i < n; i++)
                sum++;
        }

        private static void nlognfunction(BigInteger n)
        {
            double sum = 0;
            double result = 0.0;
            result = Math.Log((double)n,2);
            sum = (double)n * result; 
        }



        //ReadLine recreated for large input sizes.
        static string ReadLine()
        {
            StringBuilder sb = new StringBuilder();
            while(true){
                char ch = Convert.ToChar(Console.Read());
                sb.Append(ch);
                if(ch == '\n'){
                    break;
                }
            }

            return sb.ToString();
        }

    }//end Main
}//end namespace LabGrowthOfFunctions

Answer 1

您可以使用ReadKey（）方法。读取输入的每个字符，附加到字符串，然后将字符串转换为Int。

如何输入极长输入到控制台应用程序c＃

1 个答案: