Question

SELECT *, `o_cheque_request.member_id`, `o_cheque_request.wallet_id`
FROM `o_cheque_request`, `o_member`, o_memberinfo`
WHERE `o_cheque_request.member_id` = `o_member.member_id`
AND `o_member.member_id` = `o_memberinfo.member_id`
AND withdraw_date >='2012-07-21'
AND `o_cheque_request.member_id`
IN (SELECT `member_id` FROM `o_cheque_request` GROUP BY `member_id` HAVING SUM(gross_amount ) <=10000)
GROUP BY `o_cheque_request.withdraw_date`, `o_cheque_request.member_id` ORDER BY `request_id` DESC

这需要花费大约29秒的时间如何减少...使用加入...伙计们请帮助我... o_cheque_request的表结构
request_id bigint（20）unsigned NOT NULL auto_increment，
wallet_id int（11）NOT NULL默认＆＃39; 0＆＃39;，
member_id int（10）unsigned NOT NULL默认＆＃39; 0＆＃39;，
  withdraw_date日期默认为NULL，
  amount int（10）unsigned NOT NULL默认＆＃39; 0＆＃39;，
  gross_amount float（10,2）无符号NOT NULL默认＆＃39; 0.00＆＃39;，
  admin_charge float（10,2）无符号NOT NULL默认＆＃39; 0.00＆＃39;，
  tds float（10,2）无符号NOT NULL默认＆＃39; 0.00＆＃39;，
  repurchase float（10,2）无符号NOT NULL默认＆＃39; 0.00＆＃39;，
  net_amount float（10,2）无符号NOT NULL默认＆＃39; 0.00＆＃39;，
  withdraw_type varchar（50）默认为NULL，
  bank_name varchar（50）默认为NULL，
  cheque_no varchar（50）默认为NULL，
  courier_name varchar（50）默认为NULL，
  tracking_no varchar（50）默认为NULL，
  cheque_date日期默认＆＃39; 0000-00-00＆＃39;，
  PRIMARY KEY（request_id），
  KEY member_id（member_id）
）ENGINE = InnoDB DEFAULT CHARSET = latin1 AUTO_INCREMENT = 4738;

Answer 1

尝试这个

 SELECT * FROM (
        SELECT *, `o_cheque_request.member_id`, `o_cheque_request.wallet_id`
        FROM `o_cheque_request`
        JOIN `o_member` ON `o_cheque_request.member_id` = `o_member.member_id`
        JOIN `o_memberinfo` ON `o_member.member_id` = `o_memberinfo.member_id`
        WHERE withdraw_date >='2012-07-21'
        GROUP BY `o_cheque_request.member_id` HAVING SUM(`o_cheque_request.gross_amount` ) <=10000
    ) AS T
    GROUP BY `withdraw_date`, `member_id` ORDER BY `request_id` DESC

子节点（在/存在）到连接

1 个答案: