Question

所以，基本上，我一直在用java制作一个基于文本的游戏（这是一个像cookie clicker这样的游戏，我遇到了一个问题。你看，你键入命令的每个其他时间都没有得到任何结果。

这是代码：

import java.util.Scanner;

public class Apples {

public static int upQuarks = 0;
public static int downQuarks = 0;
public static int electrons = 0;

public static int protons = 0;
public static int neutrons = 0;

public static int HAtoms = 0;

public static int upQuarkCreation = 1;
public static int downQuarkCreation = 1;
public static int electronCreation = 1;

public static int protonCreation = 1;
public static int neutronCreation = 1;

public static int atomCreation = 1;

public static String question = "0";


public static void main(String[] args) {
    Scanner dad = new Scanner(System.in);

    while(true) {

    switch(question) {

        case "0":
            System.out.println("Welcome to this untitled text adventure game, created by Adam and Benjamin Roache.");
            System.out.println("Please enter your name.");
            question = "1";
            break;

        case "01":
            dad.next();
            question = "1A";
            break;

        case "1A":
            System.out.println("\n\nAre you sure this is your name?\n[1]Yes\n[2]No");
            switch(dad.next()) {
                case "1":
                   System.out.println("Type help to get help.");
                   question = "2";
                   break;

                case "2":
                   System.out.println("\n\n");
                   question = "0";
                   break;


            }

        case "2":
            switch(dad.next()) {
                case "help":
                    if (electrons >=1 && protons >= 1) {
                        System.out.println("\n\nTo go to the Atom Creator, type atom.");

                    }
                    if (upQuarks >= 2 && downQuarks >= 2) {
                    } else {
                        System.out.println("\n\nTo create a Proton, type pro.\nTo create a Neutron, type neu.");
                        break;
                    }
                    System.out.println("\nTo create an Up Quark, type upq.\nTo create a Down Quark, type dwnq.\nTo create a electron, type el.\nTo go to your inventory, type in.");
                    break;

                case "upq":
                    upQuarks += upQuarkCreation;
                    System.out.println("\n\nYou have 1 new Up Quark.");
                    break;

                case "dwnq":
                    downQuarks += downQuarkCreation;
                    System.out.println("\n\nYou have 1 new Down Quark.");
                    break;

                case "el":
                    electrons += electronCreation;
                    System.out.println("\n\nYou have 1 new Electron.");
                    break;

                case "pro":
                    if (upQuarks >= 2 && downQuarks >= 1) {
                        protons += protonCreation;
                        upQuarks -= 2;
                        downQuarks -= 1;
                        System.out.println("\n\nYou have 1 new proton.");
                        break;
                    }else{
                        System.out.println("\n\nYou don't have those materials yet.");
                        break;
                    }

                case "neu":
                    if (downQuarks >= 2 && upQuarks >=1) {
                        neutrons += neutronCreation;
                        upQuarks -= 1;
                        downQuarks -= 2;
                        System.out.println("\n\nYou have 1 new neutron.");
                        break;
                    }else{
                        System.out.println("\n\nYou don't have those materials yet.");
                        break;
                    }

                case "atom":
                    if(protons >= 1 && electrons >=1){
                        System.out.println("\n\nWelcome to the Atom Creator!");
                        question = "3";
                        break;
                    }else{
                        System.out.println("\n\nYou can't acsess this yet.");
                        break;
                    }


                case "in":
                    if (protons >= 1 || neutrons >=1) {
                        System.out.println("\n\n" + protons + " protons, \n" + neutrons + " neutrons.");
                        break;
                    }
                    System.out.println("\n\n" + upQuarks + " up quarks, \n" + downQuarks + " down Quarks, \nand " + electrons + " electrons.");
                    break;

            }
        break;
        case "3":
            switch(dad.next()){

                case "help":
                    System.out.println("\n\nTo create an atom, type in its atomic symbol.");
                    break;

                case "H":
                    if(protons >= 1 && electrons >= 1) {
                        HAtoms += atomCreation;
                        protons -= 1;
                        electrons -= 1;
                        System.out.println("\n\nYou have created 1 new hydrogen atom.");
                        break;
                    }else{
                        System.out.println("You don't have the right materials.");
                    }
                    break;
            }
        break;
        }
    }
}

}

代码创建这些输入命令：

“upq”=创建新的Up Quark
“dwnq”=创建新的羽绒夸克
“el”=创建新电子
“pro”=创建新的Proton（当然，如果你有合适的材料。）
“neu”=创建新的Neutron
“atom”=进入Atom Creator
“H”=产生氢原子
“help”=转到帮助部分。
“in”=进入库存

这就是所有命令。

这是输出：

欢迎来到Adam和Benjamin Roache创作的这款无题文字冒险游戏。请输入你的名字。亚当

你确定这是你的名字吗？ 1是 [2]无 1 输入帮助以获取帮助。 UPQ

你有1个新的Up Quark。 UPQ dwnq

你有1个新羽绒服。在在

1夸克， 1夸克，和0电子。 UPQ dwnq

你有1个新羽绒服。 NEU neu基因

你有一个新的中子。在在

0质子， 1个中子。

0夸克， 0夸克， 0电子。

Answer 1

使用nextLine（）或它的名称。认为这可能是一个问题

在java中制作闲置游戏

1 个答案: