Question

我复制了websocket client code ..它有效，除了它在打印Hello 1..Hello 2和Hello 3之后退出，然后它退出。我认为run_forever意味着它将永远运行，那为什么它会退出？如何让程序继续等待websocket消息？

import thread
import pdb
import websocket
import time
import requests

def on_message(ws, message):
    print message

def on_error(ws, error):
    print error

def on_close(ws):
    print "### closed ###"

def on_open(ws):
    def run(*args):
        for i in range(3):
            time.sleep(1)
            ws.send("Hello %d" % i)
        time.sleep(1)
        ws.close()
        print "thread terminating..."
    thread.start_new_thread(run, ())

if __name__ == "__main__":
    URL = "http://127.0.0.1:8000/login/"

    client = requests.session()

    EMAIL = "u234234"
    PASSWORD = "t234ri3234221"

    login_data = dict(username=EMAIL, password=PASSWORD)
    r = client.post(URL, data=login_data, headers=dict(Referer=URL))

    websocket.enableTrace(True)
    ws = websocket.WebSocketApp("ws://localhost:8080/",
                              on_message = on_message,
                              on_error = on_error,
                              on_close = on_close,
        )
    ws.on_open = on_open
    ws.run_forever()

Answer 1

我不能声称在python中使用websockets非常了解，但通常在关闭套接字时也会关闭关联的连接。因此，为了保持连接打开，我想您可能想尝试从on_open函数中删除ws.close（）行。

为什么我的程序退出而不是永远运行

1 个答案: