Question

我正在尝试通过sequlized生成此类查询：

SELECT 
    "Customers"."id", 
    (SELECT SUM("Orders"."amount") FROM "Orders"
     WHERE "Orders"."CustomerId" = "Customers"."id") AS "totalAmount",
    "Customer"."lastName" AS "Customer.lastName",
    "Customer"."firstName" AS "Customer.firstName" 
FROM "Customers" AS "Customer";

我正在尝试避免使用GROUP BY子句，因为我有很多字段可供选择，而且我不想将它们分组（我认为它效率不高，不是吗？）< / p>

我已经尝试了几种方法来实现续集，包括{include: ...}和{attributes: [[...]]}，但没有任何运气。

有什么想法吗？或者我应该使用一个大的GROUP BY子句并让所有“常规”字段按类别分组？

Answer 1

在Sequelize 4中，您可以使用attributes.include语法http://docs.sequelizejs.com/manual/tutorial/querying.html

添加其他属性

return Customer.findAll({
    attributes: {
        include: [
           [sequelize.literal('(SELECT SUM("Orders"."amount") FROM "Orders" 
            WHERE "Orders"."CustomerId" = "Customer"."id")'), 'totalAmount']
        ]
    }
});

将子查询序列化为字段

1 个答案: