我遇到了一些问题。
我想使用querydsl根据SQL编写子查询。
SQL（ps：v_task_recipient是一个视图。）
select v.title, v.create_date_time from v_task_recipient v
where
(select r.branch_id from tbl_recipient r where v.recipient_id = r.id)
in
(2704230,2703041,2702932);
在java部分，我这样写：
List<Branch> branches = user.getBranchesForPermissionOperation(Operations.claim_update);
ListSubQuery<Branch> subquery = new JPASubQuery().from(branchRecipient).where(taskRecipentView.recipient_id.eq(branchRecipient.id)).list(branchRecipient.branch);
for(Branch branch: branches)
{
ex = ex == null ? subquery.contains(branch) : ex.or(subquery.contains(branch));
}
有没有更好的解决方案来避免丑陋的for循环？我可以在＆＃39;中使用某些表达式吗？
，最困难的部分是branchRecipient继承自父收件人。
private static QRecipient recipient = QRecipient.recipient;
private static QBranchRecipient branchRecipient = recipient.as(QBranchRecipient.class);
private static QUserRecipient userRecipient = recipient.as(QUserRecipient.class);
它总是导致异常
java.lang.IllegalArgumentException：未声明的路径＆＃39;收件人＆＃39;。将此路径添加为查询的源以便能够引用它。