Question

我如何添加一个允许用户输入2 + 2或10/5之类的函数，然后只需运行对象来计算它，就像他们使用我的＆＃34手动输入它一样;输入第一个输入＆＃ 34;声明。因此，作为分配的一部分，我需要允许用户在控制台中输入类似10/5 + 1/2的内容。我还需要能够允许操作员重载，并且我不确定我的程序当前是否允许这样做。任何帮助，将不胜感激。谢谢！

#include <iostream>
#include <conio.h>

using namespace std;

class Rational
{
    private:
        float numInput;

    public:
        Rational(): numInput(0)
        {}

        void getValues()
        {           
            cout << "Enter number: ";
            cin >> numInput;
        }

        void showValues()
        {
            cout << numInput << endl;
        }

        Rational operator + (Rational) const;
        Rational operator - (Rational) const;
        Rational operator * (Rational) const;
        Rational operator / (Rational) const;
};

Rational Rational::operator + (Rational arg2) const
{
    Rational temp;
    temp.numInput = numInput + arg2.numInput;
    return temp;
}

Rational Rational::operator - (Rational arg2) const
{
    Rational temp;
    temp.numInput = numInput - arg2.numInput;
    return temp;
}

Rational Rational::operator * (Rational arg2) const
{
    Rational temp;
    temp.numInput = numInput * arg2.numInput;
    return temp;
}

Rational Rational::operator / (Rational arg2) const
{
    Rational temp;
    temp.numInput = numInput / arg2.numInput;
    return temp;
}

int main()
{
    Rational mathOb1, mathOb2, outputOb;
    int choice;
    mathOb1.getValues();
    cout << "First number entered: ";
    mathOb1.showValues();
    cout << endl;
    cout << "Enter operator: + = 1, - = 2, * = 3, / = 4  ";
    cin >> choice;
    cout << endl;
    mathOb2.getValues();
    cout << "Second number entered: ";
    mathOb2.showValues();    cout << endl;

    switch (choice)
    {
        case 1:
            outputOb = mathOb1 + mathOb2;
            break;
        case 2:
            outputOb = mathOb1 - mathOb2;
            break;
        case 3:
            outputOb = mathOb1 * mathOb2;
            break;
        case 4:
            outputOb = mathOb1 / mathOb2;
            break;
        default:
            cout << "Invalid choice! " << endl;
    }
    cout << "Answer: ";
    outputOb.showValues();
    cout << endl;

    return 0;
}

Answer 1

你不能使用cin >> {int}，如果你提供char就会失败，而且你会被困在那里。

只需使用std::getline并从那里解析出令牌：

std::string expression;
std::getline(std::cin, expression);

然后，您可以使用多种方法中的任意一种方法将string拆分为this question中表达的标记，并循环遍历标记并根据它们是运算符还是数字来解释它们。

如何允许用户输入数字和运算符？

1 个答案: