从int转换为(16位)__ m128i

时间:2015-01-30 00:09:02

标签: c x86 simd sse3

我将以下代码作为程序的一部分,但是当我编译它时,我收到以下错误:

cannot convert ‘int’ to ‘__m128i {aka __vector(2) long long int}’ in assignment

代码是:

int t;
int s;
__m128i *array;
__m128i vector;

posix_memalign ((void **) &array, BYTE_ALIGNMENT, n * m * sizeof(__m128i) );

int l=0;
for (int i=0; i<n; i++)
{
  for (int j=0; j<m; j++)
  {
    array[l] = (condition) ? t : s;   // fill the array elements with s or t 
    l++;
  }
}
vector = _mm_load_si128( &array[index]);

问题出在这一行

array[l] = (condition) ? t : s;

我找到了__m128i _mm_cvtsi32_si128(int a)指令但不幸的是,它只用于32位元素,而我有16位元素(向量大小为8)。

1 个答案:

答案 0 :(得分:0)

最后,我发现此更新工作正常

int t;
int s;
int16_t *array;
__m128i vector;

posix_memalign ((void **) &array, BYTE_ALIGNMENT, n * m * sizeof(int16_t) );

int l=0;
for (int i=0; i<n; i++)
{
  for (int j=0; j<m; j++)
  {
    array[l] = (condition) ? t : s;   // fill the array elements with s or t 
    l++;
  }
}
vector = _mm_load_si128( (__m128i*)&array[index]);

谢谢大家