即使满足条件，Java程序也会在循环时跳过

Question

当我运行我的程序时，它完全跳过第二个while循环（ while（getCard ==＆＃34; y＆＃34;））并且不循环第一个while循环，即使< em> playAgain =＆＃34; y＆＃34; 。它在程序开始时进入循环，但退出整个程序，没有错误信息，在＆＃34之后;你想再玩一次吗？ （y / n）：＆＃34; 得到解答。

这是星期二午夜时分，我无法弄清楚出了什么问题。

    import java.util.Scanner;
    import java.util.Random;

public class BlackjackGame 
{
    public static void main(String[] args) 
    {
        //declare variables
        int card1, card2, newCard, total = 0;
        String getCard, playAgain = "y";

        //set up Scanner and Random objects
        Scanner keyboard = new Scanner (System.in);
        Random rand = new Random ();

        while (playAgain == "y")
        {
            //Draw two cards and calculate total
            card1 = rand.nextInt(11) + 1;
            card2 = rand.nextInt(11) + 1;
            total = card1 + card2;

            //Display cards and total
            System.out.println("First cards: " + card1 + ", " + card2);
            System.out.println("Total: " + total);

            //Ask user if they want another card
            System.out.print ("Do you want another card? (y/n): ");
            getCard = keyboard.nextLine();

            while (getCard == "y") 
            {
                //Draw another card
                newCard = rand.nextInt(10) + 1;
                total += newCard;

                //Display new card and new total
                System.out.println ("Card: " + newCard);
                System.out.println ("Total: " + total);

                if (total > 21)
                {
                    System.out.println ("Bust!");
                    getCard = "n";
                }
                else if (total == 21)
                {
                    System.out.println ("Blackjack!");
                    getCard = "n";
                }
                else
                {
                    System.out.print ("Do you want another card? (y/n): ");
                    getCard = keyboard.nextLine();
                }
            }

            //Ask if user wants to play again.
            System.out.print ("Would you like to play again? (y/n): ");
            playAgain = keyboard.nextLine();
        }
    }
}