Question

我试图绘制字典中某些键（标题为＆＃39; hat1＆＃39;至＆＃39; hat10＆＃39;）的数字1,2和3的频率。将我的数据（如下所示）转换为我可以绘制的格式。

data = {'hat9': [[1, 2, 3, 1, 2]], 'hat8': [[1, 2, 3, 2, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3]], 'hat1': [[1, 2, 3]], 'hat3': [[1, 2, 3, 1, 2, 2, 2, 1, 2, 2, 2, 2, 1, 1, 1, 1, 1, 1, 2, 2, 2, 1, 1]], 'hat2': [[1, 2, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1]], 'hat5': [[1, 2, 3, 2, 3, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 1, 1, 3, 3, 3, 3, 3, 3, 1, 3, 2, 3, 2, 3, 2, 3, 3, 3, 3, 2, 3, 1, 3, 3, 3, 3]], 'hat4': [[1, 2, 3, 1, 2, 1, 1, 1, 2, 1, 1, 1, 1, 3, 1, 1, 1, 2, 1, 1, 2, 1, 1, 2, 3, 1, 2, 1, 3, 2, 1, 3, 1, 1, 1, 1, 1, 1, 3, 1]], 'hat7': [[1, 2, 3, 2, 2, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2]], 'hat6': [[1, 2, 3, 1, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 1, 3, 3, 3, 3, 1, 1, 3]], 'hat10': [[1, 2, 3, 3, 3, 3, 3, 3, 1, 2, 2, 1, 2, 3, 3, 2, 3, 3, 3, 3, 3, 2, 1, 1, 3, 3, 1, 2, 2, 3, 3, 1, 3, 3, 3, 3, 3, 2, 3, 1, 3, 1, 3, 1, 3, 3, 3, 3, 3, 3, 3, 1, 3, 3, 3, 3, 3, 3, 3, 3, 3, 1, 1, 3, 3, 3, 3, 2, 1, 3, 2, 1, 3, 2, 3, 3, 1, 2, 1, 2, 3, 3, 1, 3, 2, 2, 1, 2, 3, 3, 1, 2, 3, 2, 3, 3, 1, 3, 3, 3, 3]]}

当我跑DataFrame.from_dict(data)时，我收到的输出看起来像这样：

In [100]: DataFrame.from_dict(data)
Out[100]: 
        hat1                                              hat10  \
0  [1, 2, 3]  [1, 2, 3, 3, 3, 3, 3, 3, 1, 2, 2, 1, 2, 3, 3, ...   

                                                hat2  \
0  [1, 2, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, ...   

                                                hat3  \
0  [1, 2, 3, 1, 2, 2, 2, 1, 2, 2, 2, 2, 1, 1, 1, ...   

                                                hat4  \
0  [1, 2, 3, 1, 2, 1, 1, 1, 2, 1, 1, 1, 1, 3, 1, ...   

                                                hat5  \
0  [1, 2, 3, 2, 3, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, ...   

                                                hat6  \
0  [1, 2, 3, 1, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, ...   

                                            hat7  \
0  [1, 2, 3, 2, 2, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2]   

                                                hat8             hat9  
0  [1, 2, 3, 2, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, ...  [1, 2, 3, 1, 2]

我希望有人可以帮助我将数据转换为更可行的格式，可以相对轻松地转换为图形。谢谢你的帮助。

Answer 1

试试这个：

data = {'hat9': [[1, 2, 3, 1, 2]], 'hat8': [[1, 2, 3, 2, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3]], 'hat1': [[1, 2, 3]], 'hat3': [[1, 2, 3, 1, 2, 2, 2, 1, 2, 2, 2, 2, 1, 1, 1, 1, 1, 1, 2, 2, 2, 1, 1]], 'hat2': [[1, 2, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1]], 'hat5': [[1, 2, 3, 2, 3, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 1, 1, 3, 3, 3, 3, 3, 3, 1, 3, 2, 3, 2, 3, 2, 3, 3, 3, 3, 2, 3, 1, 3, 3, 3, 3]], 'hat4': [[1, 2, 3, 1, 2, 1, 1, 1, 2, 1, 1, 1, 1, 3, 1, 1, 1, 2, 1, 1, 2, 1, 1, 2, 3, 1, 2, 1, 3, 2, 1, 3, 1, 1, 1, 1, 1, 1, 3, 1]], 'hat7': [[1, 2, 3, 2, 2, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2]], 'hat6': [[1, 2, 3, 1, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 1, 3, 3, 3, 3, 1, 1, 3]], 'hat10': [[1, 2, 3, 3, 3, 3, 3, 3, 1, 2, 2, 1, 2, 3, 3, 2, 3, 3, 3, 3, 3, 2, 1, 1, 3, 3, 1, 2, 2, 3, 3, 1, 3, 3, 3, 3, 3, 2, 3, 1, 3, 1, 3, 1, 3, 3, 3, 3, 3, 3, 3, 1, 3, 3, 3, 3, 3, 3, 3, 3, 3, 1, 1, 3, 3, 3, 3, 2, 1, 3, 2, 1, 3, 2, 3, 3, 1, 2, 1, 2, 3, 3, 1, 3, 2, 2, 1, 2, 3, 3, 1, 2, 3, 2, 3, 3, 1, 3, 3, 3, 3]]}


keys = []
values = []
for key,value in data.iteritems():
    keys.append(key)
    a = 0
    b = 0
    c = 0
    for x in value[0]:
        if x==1: a+=1;
        elif x ==2: b+=1;
        elif x==3: c+=1;
    values.append([a,b,c])

print keys
print values

希望这会有所帮助。密钥为['hat9', 'hat8', etc.,..]和values = [[freq of 1 in 'hats9', freq of 2 in 'hats9', freq of 3 in 'hats9'], [freq of 1 in 'hats8', freq of 2 in 'hats8', freq of 3 in 'hats8'],..]（3个项目列表的列表）

Answer 2

如果您想使用Matplotlib创建直方图，那么除了要显示每个hist的{{1}}方法之外，您真的不需要做更多的事情。例如，

hat

（您需要在import pylab pylab.hist(data['hat4'][0], bins=(1,2,3,4), align='left')处索引，因为由于某种原因，每个字典值都是长度为1的列表，单个项本身就是数据值列表。

如果你需要以某种方式聚合帽子，你需要说明如何。

enter image description here

如果您愿意，可以使用pandas [0]执行相同操作：

DataFrame

从列表的dict创建直方图

2 个答案: