Question

我有一个.txt文件，其中包含以下信息，用于显示用户名，然后是3个在测验中得分的分数：

callum,10,7,9
carl,10,10,10
hollie,1,4,7
brad,4,8,3
kyle,7,2,0

我希望sort按字母顺序显示用户名后的最高分。

Answer 1

阅读文件内容。
使用readlines()方法从文件中读取行。
使用split()获取姓名和分数。
添加字典：Name为Key，Value为总分。
从结果字典中获取所有keys。
用户sort()方法按字母排序列表。
按字母顺序打印结果。

代码

p = "/home/vivek/Desktop/test_input.txt"
result = {}
with open(p, "rb") as fp:
    for i in fp.readlines():
        tmp = i.split(",")
        try:
            result[(tmp[0])] = eval(tmp[1]) + eval(tmp[2]) + eval(tmp[3]) 
        except:
            pass

alphabetical_name =  result.keys()
alphabetical_name.sort()

for i in alphabetical_name:
    print "Name:%s, Highest score: %d"%(i, result[i])

输出：

$ python test.py 
Name:brad, Highest score: 15
Name:callum, Highest score: 26
Name:carl, Highest score: 30
Name:hollie, Highest score: 12
Name:kyle, Highest score: 9

Answer 2

所以我首先要隔离所有的行：

with open('filename') as f:
    lines = f.readlines()

所以我将继续假设我有一个名为line的列表，其中包含以下内容：

lines = ["callum,10,7,9","carl,10,10,10","hollie,1,4,7","brad,4,8,3","kyle,7,2,0"]

然后我将首先按名称对行进行排序

lines = sorted(lines)

然后，对于要隔离标记的每一行，对它们进行排序并将其打印回来：

for line in lines:
    #name is what there is before the first comma
    name = line[:line.find(",")]
    #marks are what there is after the second comma and are comma separated
    marks = line[line.find(",")+1:].split(",")
    #sort the marks
    marks = sorted(marks,key=int)

    #if you want to print only the highest
    print "%s,%s"%(name,marks[-1])

从python中的文件中排序信息

2 个答案: