从数据文件中提取信息?

时间:2016-03-26 13:18:48

标签: javascript arrays database sorting

我在这种格式的数据文件中有超过170000个数据条目:

1479661:-1,1,-1,-898,-769,0.00;-1,2,-1,-96,-1402,0.00;-1,3,-1,117,-1397,0.00;-1,4,-1,-4,-2420,0.00;4,5,-1,5570,4395,0.00;4,6,-1,5570,4395,0.00;4,7,-1,5570,4395,0.00;4,8,-1,5570,4395,0.00;4,9,-1,5570,4395,0.00;4,10,-1,5570,4395,0.00;4,11,-1,5570,4395,0.00;4,12,-1,5570,4395,0.00;4,13,-1,5570,4395,0.00;4,14,-1,5570,4395,0.00;-1,15,-1,913,-3533,0.00;4,16,-1,5570,4395,0.00;4,17,-1,5570,4395,0.00;4,18,-1,5570,4395,0.00;4,19,-1,5570,4395,0.00;4,20,-1,5570,4395,0.00;4,21,-1,5570,4395,0.00;4,22,-1,5570,4395,0.00;4,23,-1,5570,4395,0.00;4,24,-1,5570,4395,0.00;4,25,-1,5570,4395,0.00;4,26,-1,5570,4395,0.00;4,27,-1,5570,4395,0.00;4,28,-1,5570,4395,0.00;4,29,-1,5570,4395,0.00;:117,-1397,7,7.00,A,Dead;:

1479662:-1,1,-1,-898,-769,0.00;-1,2,-1,-96,-1402,0.00;-1,3,-1,117,-1392,0.00;-1,4,-1,-6,-2419,0.00;4,5,-1,5570,4395,0.00;4,6,-1,5570,4395,0.00;4,7,-1,5570,4395,0.00;4,8,-1,5570,4395,0.00;4,9,-1,5570,4395,0.00;4,10,-1,5570,4395,0.00;4,11,-1,5570,4395,0.00;4,12,-1,5570,4395,0.00;4,13,-1,5570,4395,0.00;4,14,-1,5570,4395,0.00;-1,15,-1,913,-3533,0.00;4,16,-1,5570,4395,0.00;4,17,-1,5570,4395,0.00;4,18,-1,5570,4395,0.00;4,19,-1,5570,4395,0.00;4,20,-1,5570,4395,0.00;4,21,-1,5570,4395,0.00;4,22,-1,5570,4395,0.00;4,23,-1,5570,4395,0.00;4,24,-1,5570,4395,0.00;4,25,-1,5570,4395,0.00;4,26,-1,5570,4395,0.00;4,27,-1,5570,4395,0.00;4,28,-1,5570,4395,0.00;4,29,-1,5570,4395,0.00;:117,-1392,7,7.07,A,Dead;:

现在每个数据数组都以唯一的id开头,我想知道是否有方便的方法将每个条目1479661然后每秒1479662推送到一个数组,并将唯一ID中的值分配给6个更新的字段。

现在我问是否有一种更方便的方式,因为目前我正在使用这种方法:

  • 数据由一行中的三个块组成
  • 将链接拆分为块

    var chunkOne = [1479661]; 
    var chunkTwo = [-1,1,-1,-898,-769,0.00,-1,2,-1,-96,-1402,0.00,-1,3,-1,117,-1397,0.00,-1,4,-1,-4,-2420,0.00,4,5,-1,5570,4395,0.00,4,6,-1,5570,4395,0.00,4,7,-1,5570,4395,0.00,4,8,-1,5570,4395,0.00,4,9,-1,5570,4395,0.00,4,10,-1,5570,4395,0.00,4,11,-1,5570,4395,0.00,4,12,-1,5570,4395,0.00,4,13,-1,5570,4395,0.00,4,14,-1,5570,4395,0.00,-1,15,-1,913,-3533,0.00,4,16,-1,5570,4395,0.00,4,17,-1,5570,4395,0.00,4,18,-1,5570,4395,0.00,4,19,-1,5570,4395,0.00,4,20,-1,5570,4395,0.00,4,21,-1,5570,4395,0.00,4,22,-1,5570,4395,0.00,4,23,-1,5570,4395,0.00,4,24,-1,5570,4395,0.00,4,25,-1,5570,4395,0.00,4,26,-1,5570,4395,0.00,4,27,-1,5570,4395,0.00,4,28,-1,5570,4395,0.00,4,29,-1,5570,4395,0.00];
    var chunkThree = [117,-1397,7,7.00,"A","Dead"];
    

然后得到每个数组的长度:

var chunkOneLength = chunkOne.length;
var chunkTwoLength = chunkTwo.length;
var chunkThreeLength = chunkThree.length;

根据数据块选择数组中的第n个值:

//uniqueID set as first
for (var i = 0; i < chunkOneLength; i = i + 1) {
  // useful code would go here
  alert("This is the unique ID " + chunkOne[i]);
}

//teamval
for (var i = 0; i < chunkTwoLength; i = i + 6) {
  // useful code would go here
  alert("This is the teamVal " + chunkTwo[i]);
}

现在我用这种方法看到的唯一问题是,每次都需要格式化原始数据数组并将其分成块。

3 个答案:

答案 0 :(得分:0)

由于每个部分都有一个分隔符,即:,您实际上可以使用split将它们拆分为如下所示并将它们推入数组中,只需要进行2次循环 - 首先推动分割数组在一个新数组中,然后循环遍历它们并填充结构。

请注意,只要每个数据块都以:分隔,即使您稍后展开数据,也可以使用任何数据。显然,如果删除:分隔符,它将无效。

以下示例:

var splitChucks = [];
var chucks = [ "1479661:-1,1,-1,-898,-769,0.00;-1,2,-1,-96,-1402,0.00;-1,3,-1,117,-1397,0.00;-1,4,-1,-4,-2420,0.00;4,5,-1,5570,4395,0.00;4,6,-1,5570,4395,0.00;4,7,-1,5570,4395,0.00;4,8,-1,5570,4395,0.00;4,9,-1,5570,4395,0.00;4,10,-1,5570,4395,0.00;4,11,-1,5570,4395,0.00;4,12,-1,5570,4395,0.00;4,13,-1,5570,4395,0.00;4,14,-1,5570,4395,0.00;-1,15,-1,913,-3533,0.00;4,16,-1,5570,4395,0.00;4,17,-1,5570,4395,0.00;4,18,-1,5570,4395,0.00;4,19,-1,5570,4395,0.00;4,20,-1,5570,4395,0.00;4,21,-1,5570,4395,0.00;4,22,-1,5570,4395,0.00;4,23,-1,5570,4395,0.00;4,24,-1,5570,4395,0.00;4,25,-1,5570,4395,0.00;4,26,-1,5570,4395,0.00;4,27,-1,5570,4395,0.00;4,28,-1,5570,4395,0.00;4,29,-1,5570,4395,0.00;:117,-1397,7,7.00,A,Dead;:", "1479662:-1,1,-1,-898,-769,0.00;-1,2,-1,-96,-1402,0.00;-1,3,-1,117,-1392,0.00;-1,4,-1,-6,-2419,0.00;4,5,-1,5570,4395,0.00;4,6,-1,5570,4395,0.00;4,7,-1,5570,4395,0.00;4,8,-1,5570,4395,0.00;4,9,-1,5570,4395,0.00;4,10,-1,5570,4395,0.00;4,11,-1,5570,4395,0.00;4,12,-1,5570,4395,0.00;4,13,-1,5570,4395,0.00;4,14,-1,5570,4395,0.00;-1,15,-1,913,-3533,0.00;4,16,-1,5570,4395,0.00;4,17,-1,5570,4395,0.00;4,18,-1,5570,4395,0.00;4,19,-1,5570,4395,0.00;4,20,-1,5570,4395,0.00;4,21,-1,5570,4395,0.00;4,22,-1,5570,4395,0.00;4,23,-1,5570,4395,0.00;4,24,-1,5570,4395,0.00;4,25,-1,5570,4395,0.00;4,26,-1,5570,4395,0.00;4,27,-1,5570,4395,0.00;4,28,-1,5570,4395,0.00;4,29,-1,5570,4395,0.00;:117,-1392,7,7.07,A,Dead;:"];
  
for (var i = 0; i < chucks.length; i++){
  splitChucks.push(chucks[i].split(':'))
}

for (var h = 0; h < splitChucks.length; h++) {
    alert("This is the unique ID " + splitChucks[h][0]);
    alert("This is the teamVal " + splitChucks[h][1]);
}

希望这会有所帮助,这是一种更有效的方式来完成任务:)

答案 1 :(得分:0)

var splitChucks = [];
var chucks = [ "1479661:-1,1,-1,-898,-769,0.00;-1,2,-1,-96,-1402,0.00;-1,3,-1,117,-1397,0.00;-1,4,-1,-4,-2420,0.00;4,5,-1,5570,4395,0.00;4,6,-1,5570,4395,0.00;4,7,-1,5570,4395,0.00;4,8,-1,5570,4395,0.00;4,9,-1,5570,4395,0.00;4,10,-1,5570,4395,0.00;4,11,-1,5570,4395,0.00;4,12,-1,5570,4395,0.00;4,13,-1,5570,4395,0.00;4,14,-1,5570,4395,0.00;-1,15,-1,913,-3533,0.00;4,16,-1,5570,4395,0.00;4,17,-1,5570,4395,0.00;4,18,-1,5570,4395,0.00;4,19,-1,5570,4395,0.00;4,20,-1,5570,4395,0.00;4,21,-1,5570,4395,0.00;4,22,-1,5570,4395,0.00;4,23,-1,5570,4395,0.00;4,24,-1,5570,4395,0.00;4,25,-1,5570,4395,0.00;4,26,-1,5570,4395,0.00;4,27,-1,5570,4395,0.00;4,28,-1,5570,4395,0.00;4,29,-1,5570,4395,0.00;:117,-1397,7,7.00,A,Dead;:", "1479662:-1,1,-1,-898,-769,0.00;-1,2,-1,-96,-1402,0.00;-1,3,-1,117,-1392,0.00;-1,4,-1,-6,-2419,0.00;4,5,-1,5570,4395,0.00;4,6,-1,5570,4395,0.00;4,7,-1,5570,4395,0.00;4,8,-1,5570,4395,0.00;4,9,-1,5570,4395,0.00;4,10,-1,5570,4395,0.00;4,11,-1,5570,4395,0.00;4,12,-1,5570,4395,0.00;4,13,-1,5570,4395,0.00;4,14,-1,5570,4395,0.00;-1,15,-1,913,-3533,0.00;4,16,-1,5570,4395,0.00;4,17,-1,5570,4395,0.00;4,18,-1,5570,4395,0.00;4,19,-1,5570,4395,0.00;4,20,-1,5570,4395,0.00;4,21,-1,5570,4395,0.00;4,22,-1,5570,4395,0.00;4,23,-1,5570,4395,0.00;4,24,-1,5570,4395,0.00;4,25,-1,5570,4395,0.00;4,26,-1,5570,4395,0.00;4,27,-1,5570,4395,0.00;4,28,-1,5570,4395,0.00;4,29,-1,5570,4395,0.00;:117,-1392,7,7.07,A,Dead;:"];
  
for (var i = 0; i < chucks.length; i++){
  splitChucks.push(chucks[i].split(':'))
}

for (var h = 0; h < splitChucks.length; h++) {
    alert("This is the unique ID " + splitChucks[h][0]);
    alert("This is the teamVal " + splitChucks[h][1]);
}

答案 2 :(得分:-1)

唯一ID的最佳目的之一是充当索引。因此,不要迭代索引数组(chunkOne),而是使用ID作为Object键!

// 1479661:-1,1,-1,-898,-769,0.00;-1,2,-1,-96,-1402,0.00;-1,3,-1,117,-1397,0.00;-1,4,-1,-4,-2420,0.00;4,5,-1,5570,4395,0.00;4,6,-1,5570,4395,0.00;4,7,-1,5570,4395,0.00;4,8,-1,5570,4395,0.00;4,9,-1,5570,4395,0.00;4,10,-1,5570,4395,0.00;4,11,-1,5570,4395,0.00;4,12,-1,5570,4395,0.00;4,13,-1,5570,4395,0.00;4,14,-1,5570,4395,0.00;-1,15,-1,913,-3533,0.00;4,16,-1,5570,4395,0.00;4,17,-1,5570,4395,0.00;4,18,-1,5570,4395,0.00;4,19,-1,5570,4395,0.00;4,20,-1,5570,4395,0.00;4,21,-1,5570,4395,0.00;4,22,-1,5570,4395,0.00;4,23,-1,5570,4395,0.00;4,24,-1,5570,4395,0.00;4,25,-1,5570,4395,0.00;4,26,-1,5570,4395,0.00;4,27,-1,5570,4395,0.00;4,28,-1,5570,4395,0.00;4,29,-1,5570,4395,0.00;:117,-1397,7,7.00,A,Dead;:

var data = 
{
    1479661:
    [
        -1,1,-1,-898,-769,0.00,-1,2,-1,-96,-1402,0.00,-1,3,-1,117,-1397,0.00,-1,4,-1,-4,-2420,0.00,4,5,-1,5570,4395,0.00,4,6,-1,5570,4395,0.00,4,7,-1,5570,4395,0.00,4,8,-1,5570,4395,0.00,4,9,-1,5570,4395,0.00,4,10,-1,5570,4395,0.00,4,11,-1,5570,4395,0.00,4,12,-1,5570,4395,0.00,4,13,-1,5570,4395,0.00,4,14,-1,5570,4395,0.00,-1,15,-1,913,-3533,0.00,4,16,-1,5570,4395,0.00,4,17,-1,5570,4395,0.00,4,18,-1,5570,4395,0.00,4,19,-1,5570,4395,0.00,4,20,-1,5570,4395,0.00,4,21,-1,5570,4395,0.00,4,22,-1,5570,4395,0.00,4,23,-1,5570,4395,0.00,4,24,-1,5570,4395,0.00,4,25,-1,5570,4395,0.00,4,26,-1,5570,4395,0.00,4,27,-1,5570,4395,0.00,4,28,-1,5570,4395,0.00,4,29,-1,5570,4395,0.00,117,-1397,7,7.00,"A","Dead"
    ]
    // More data...
};

Object.keys(data).forEach(function(key)
{
     console.log('This is ID ' + key);

     data[key].forEach(function(value,index,array)
     {
          console.log('Index ' + index + ' of data key ' + key + ':');
          console.log(data[key][index]);
     });
});

在任何现代浏览器的控制台或node.js实例上测试,以查看结果。