我有下一个数据表:
id date another_info
1 2014-02-01 lala
1 2014-03-11 ajskj
1 2014-05-13 kgfd
2 2014-02-01 SADA
3 2014-02-01 sfdg
3 2014-06-12 fdsA
4 2015-01-03 lilo
4 2015-01-07 kjlk
我想附加列'sequence_number':
id date sequance_number another_info
1 2014-02-01 1 lala
1 2014-03-11 2 ajskj
1 2014-05-13 3 kgfd
2 2014-02-01 1 SADA
3 2014-02-01 1 sfdg
3 2014-06-12 2 fdsA
4 2015-01-03 1 lilo
4 2015-01-07 2 kjlk
对于每个id,我计算行。表应按id,date
排序答案 0 :(得分:3)
select id,"date",another_info, row_number() OVER (ORDER BY id,"date") as sequence_number
from data_table
[编辑]没有意识到您需要按ID进行分区。
SELECT id,"date",another_info,
row_number() OVER (PARTITION BY id ORDER BY "date") as sequence_number
FROM data_table