Question

我试图解决这个问题超过两个小时。我需要你的帮助。我想使用此查询对两个表中的数据进行排序：

SELECT *
FROM (

SELECT INV.`id` , INV.`userid` , Cli.firstname, Cli.lastname,   Cli.companyname, Cli.currency, INV.`total` , INV.`date` , INV.`duedate`
FROM tblinvoices AS INV, tblclients Cli
WHERE now( ) >= DATE_ADD( INV.duedate, INTERVAL +2
DAY )
AND INV.STATUS = 'unpaid'
AND Cli.id = INV.userid
AND INV.total >=200
AND INV.`date` != INV.`duedate`
) AS X
ORDER BY X.duedate ASC

我得到了这个结果：

id  userid firstname    lastname    companyname     currency    total   date    duedate 
3   3   younes  Abakarim        1   154877.00   2014-10-18  2014-11-01
9   12  Faissal Marouan 1   2568.00     2014-10-23  2014-11-06
34  3   younes  Abakarim        1   252.60  2015-01-10  2015-01-15
31  12  Faissal Marouan 1   288.00  2015-01-01  2015-01-15
36  3   younes  Abakarim    Bestgallery 1   288.00  2015-01-16  2015-01-19

但我想要的是：

id  userid  firstname   lastname    companyname     currency    total   date    duedate 
3   3   younes  Abakarim        1   154877.00   2014-10-18  2014-11-01
34  3   younes  Abakarim        1   252.60  2015-01-10  2015-01-15
36  3   younes  Abakarim    Bestgallery 1   288.00  2015-01-16  2015-01-19
9   12  Faissal Marouan 1   2568.00     2014-10-23  2014-11-06
31  12  Faissal Marouan 1   288.00  2015-01-01  2015-01-15

仍按duedate排序。

Answer 1

使用逗号添加第二个排序属性：

SELECT *
FROM (

SELECT INV.`id` , INV.`userid` , Cli.firstname, Cli.lastname,   Cli.companyname, Cli.currency, INV.`total` , INV.`date` , INV.`duedate`
FROM tblinvoices AS INV, tblclients Cli
WHERE now( ) >= DATE_ADD( INV.duedate, INTERVAL +2
DAY )
AND INV.STATUS = 'unpaid'
AND Cli.id = INV.userid
AND INV.total >=200
AND INV.`date` != INV.`duedate`
) AS X
ORDER BY X.userid ASC, x.duedate ASC

Answer 2

使用此：

SELECT *
FROM (
SELECT INV.`id`
    ,INV.`userid`
    ,Cli.firstname
    ,Cli.lastname
    ,Cli.companyname
    ,Cli.currency
    ,INV.`total`
    ,INV.`date`
    ,INV.`duedate`
FROM tblinvoices AS INV
    ,tblclients Cli
WHERE now() >= DATE_ADD(INV.duedate, INTERVAL + 2 DAY)
    AND INV.STATUS = 'unpaid'
    AND Cli.id = INV.userid
    AND INV.total >= 200
    AND INV.`date` != INV.`duedate`
) AS X
ORDER BY x.userid ASC
,X.duedate ASC;

Answer 3

试试这个 - 添加group by子句：

SELECT *
FROM (

SELECT INV.`id` , INV.`userid` , Max(Cli.firstname) firstname, Max(Cli.lastname) lastname,  Max(Cli.companyname) companyname, Max(Cli.currency) currency, Max(INV.`total`) total , Max(INV.`date`) date , Max(INV.`duedate`) duedate
FROM tblinvoices AS INV, tblclients Cli
WHERE now( ) >= DATE_ADD( INV.duedate, INTERVAL +2
DAY )
AND INV.STATUS = 'unpaid'
AND Cli.id = INV.userid
AND INV.total >=200
AND INV.`date` != INV.`duedate`
group by INV.userid, INV.id) AS X
ORDER BY X.duedate ASC

Answer 4

首先，您应该修复您的查询，以便它使用正确的join语法并且有点可读：

SELECT *
FROM (SELECT INV.`id` , INV.`userid` , Cli.firstname, Cli.lastname, 
             Cli.companyname, Cli.currency,
             INV.`total` , INV.`date` , INV.`duedate`
      FROM tblinvoices INV JOIN
           tblclients Cli
           ON Cli.id = INV.userid
      WHERE NOW() >= DATE_ADD(INV.duedate, INTERVAL + 2 DAY) AND
            INV.STATUS = 'unpaid' AND
            INV.total >= 200 AND
            INV.`date` <> INV.`duedate`
     ) ic
ORDER BY Xic.duedate ASC;

接下来，获得你想要的东西有点复杂。您希望每个客户都有相同的截止日期。这需要加入。如果MySQL支持CTE，这将更加简单，但唉：

SELECT ic.*
FROM (SELECT INV.`id` , INV.`userid` , Cli.firstname, Cli.lastname, 
             Cli.companyname, Cli.currency,
             INV.`total` , INV.`date` , INV.`duedate`
      FROM tblinvoices INV JOIN
           tblclients Cli
           ON Cli.id = INV.userid
      WHERE NOW() >= DATE_ADD(INV.duedate, INTERVAL + 2 DAY) AND
            INV.STATUS = 'unpaid' AND
            INV.total >= 200 AND
            INV.`date` <> INV.`duedate`
     ) ic JOIN
     (SELECT INV.`userid`, MAX(INV.`duedate`) as maxdd
      FROM tblinvoices INV
      WHERE NOW() >= DATE_ADD(INV.duedate, INTERVAL + 2 DAY) AND
            INV.STATUS = 'unpaid' AND
            INV.total >= 200 AND
            INV.`date` <> INV.`duedate`
      GROUP BY INV.`userid`
     ) ud
     ON ic.userid = ud.userid
ORDER BY ud.maxdd ASC, ic.userid;

我不确定您是否需要排序的截止日期的最大值或最小值。这两个是相同的例子。

SQL ORDER BY有两个条件

4 个答案: