我有这个数组:
declare -A modeAndAction
modeAndAction[category]=create
modeAndAction[attribute]=create
modeAndAction[customers]=create
modeAndAction[newsletter]=create
modeAndAction[vouchers]=create
modeAndAction[products]=create
modeAndAction[orders]=create
哪个输出:
Starting import of mode : attribute
With action: create
Starting import of mode : category
With action: create
Starting import of mode : newsletter
With action: create
Starting import of mode : vouchers
With action: create
Starting import of mode : orders
With action: create
Starting import of mode : customers
With action: create
Starting import of mode : products
With action: create
但我希望这个输出:
Starting import of mode : category
With action: create
Starting import of mode : attribute
With action: create
Starting import of mode : customer
With action: create
Starting import of mode : newsletter
With action: create
Starting import of mode : vouchers
With action: create
Starting import of mode : products
With action: create
Starting import of mode : orders
With action: create
所以一切都在输出中移动,忽略了它的声明,但我不明白为什么。 我希望模式(+它的动作)完全按照我声明的数组的顺序调用。
Bash版本:
GNU bash, version 4.2.51(1)-release (x86_64-pc-linux-gnu)
//编辑 我发现如果我有这个数组
modeAndAction[AAAAAAAAA]=create;
modeAndAction[B]=create;
modeAndAction[C]=create;
modeAndAction[D]=create;
我得到了这个输出:
Starting import of mode : B
With action: create
Starting import of mode : C
With action: create
Starting import of mode : D
With action: create
Starting import of mode : AAAAAAAAA
With action: create
所以它按关键长度自动排序。
// EDIT2 负责输出的代码
for i in "${!modeAndAction[@]}"
do
echo "Starting import of mode : $i"
echo "With action: ${modeAndAction[$i]}"
done
答案 0 :(得分:1)
现在使用非关联数组键解决它:
modeAndAction[0]=category
modeAndAction[1]=attribute
modeAndAction[2]=customers
modeAndAction[3]=newsletter
modeAndAction[4]=vouchers
modeAndAction[5]=products
modeAndAction[6]=orders
for i in "${!modeAndAction[@]}"
do
echo "Starting import of mode : ${modeAndAction[$i]} with action create"
# ...
done