Question

以下是工作代码的“主要”主体：

public class ArrayFunHouse
{
    //instance variables and constructors could be used, but are not really needed

    //getSum() will return the sum of the numbers from start to stop, not including stop
    public static int getSum(int[] numArray, int start, int stop)
    {
        int sum = 0;

        for(int count = start; count <= stop; count++) {
            sum += numArray[count];
        }
        return sum;
    }

    //getCount() will return number of times val is present
    public static int getCount(int[] numArray, int val)
    {
        int present = 0;

        for(int count = 0; count < numArray.length; count++) {
            if(numArray[count] == val) {
                present++;
            }
        }
        return present;
    }

    public static int[] removeVal(int[] numArray, int val)
    {
        int[] removal = new int[numArray.length - getCount(numArray, val)];
        int arbitrary = 0;

        for(int count = 0; count < removal.length; count++) {
            if(numArray[count] == val) {
                arbitrary++;
            } else {
                removal[count - arbitrary] = numArray[count];
            }
        }

        return removal;
    }
}

跑步者班：

import java.util.Arrays;

public class ArrayFunHouseRunner
{
public static void main( String args[] )
{
    int[] one = {4,10,0,1,7,6,5,3,2,9};

    System.out.println(Arrays.toString(one));
    System.out.println("sum of spots 3-6  =  " + ArrayFunHouse.getSum(one,3,6));
    System.out.println("sum of spots 2-9  =  " + ArrayFunHouse.getSum(one,2,9));
    System.out.println("# of 4s  =  " + ArrayFunHouse.getCount(one,4));
    System.out.println("# of 9s  =  " + ArrayFunHouse.getCount(one,9));
    System.out.println("# of 7s  =  " + ArrayFunHouse.getCount(one,7));
    System.out.println("new array with all 7s removed = "+     ArrayFunHouse.removeVal(one, 7));


}
}

返回一些我试图打印没有toString的类的东西，即：

[4, 10, 0, 1, 7, 6, 5, 3, 2, 9]
sum of spots 3-6  =  19
sum of spots 2-9  =  33
number of 4s  =  1
number of 9s  =  1
number of 7s  =  1
new array with all 7s removed = [I@56f7ce53

我知道我在跑步者中正确称呼它，没有太多搞砸，无法查明问题，有什么建议吗？

最终编辑：这太令人尴尬了。问题实际上是在跑步者中，而不是调用Arrays.toString。

Answer 1

打印

System.out.println(Arrays.toString(array));

如果你的数组里面有数组。

System.out.println(Arrays.deepToString(array));

Answer 2

正如您所说，您正在打印返回数组的toString()。但是，在Java中，数组不会覆盖toString()，因此您将获得输出。不要只打印返回的值，而是使用Arrays.toString(int[])打印它的值 - 这应该可以为您提供所需的输出。

返回数组方法的奇怪输出

2 个答案: