Question

如何从字母表中猜出来信？因此，如果第一个猜测是AABB，我需要从字母表字母表中获取A和B，以便在没有字母A和B的情况下进行新的随机猜测。

    randomCode.clear();//Clears the random code ArrayList to put a new one in it
    Random r = new Random();
    String alphabet = "ABCDEF";
    StringBuilder result = new StringBuilder(randomCode.size());

    if(turn == 0){
        guess = "AABB";

    }else{
        if(blackPin == 0 && whitePin ==0){
            for (int c = 0; c < 4; c++) {
                if(alphabet.charAt(c) == guess.charAt(c)){

                }
                randomCode.add(alphabet.charAt(r.nextInt(alphabet.length())));//generate 4 random letters with the letters ABCDEF and put in arrayList
            }
            for (Character c : randomCode){//Converts Char[] randomCode to a String
                result.append(c);
                }
            guess = result.toString();//Gives the String guess 4 random letters.

Answer 1

为什么要在可以避免的情况下循环：

String abd = "ABCDEF";
String guess = "AABB";
System.out.println(abd.replaceAll(String.join("|", guess.split("")), ""));

打印：

CDEF

Answer 2

如果您有ArrayList，例如：

ArrayList<Character> alphabet = new ArrayList<>(Arrays.asList('A', 'B', 'C', 'D'));

和String：

String guess = "AABB";

您可以从猜测中的字母中删除字母，如下所示：

for (int i = 0; i < guess.length(); i++)
    alphabet.remove(new Character(guess.charAt(i)));

现在，如果打印出字母：

for (int i = 0; i < alphabet.size(); i++)
    System.out.print(alphabet.get(i));

输出结果为："CD"。

你可以一起使用：

ArrayList<Character> alphabet = new ArrayList<>(Arrays.asList('A', 'B', 'C', 'D'));
Random random = new Random();
String guess = "";

while (true) {
    /* init a guess */
    guess = "";
    for (int j = 0; j < 4; j++)
        guess += alphabet.get(random.nextInt(alphabet.size()));
    System.out.println("The guess is: " + guess);

    /* remove letters */
    for (int j = 0; j < guess.length(); j++)
        alphabet.remove(new Character(guess.charAt(j)));

    /* the alphabet is empty */
    if (alphabet.isEmpty()) {
        System.out.println("The alphabet is empty");
        break;
    }
}

Answer 3

最有效的方法是利用字母的ASCII码是26个连续的整数，并从char转换为int。代码65-68是ABCD。

http://www.ascii-code.com/

在for循环中删除字符串中的字母

3 个答案: