Question

这是我要解析的xml ..

<object pk="1" model="test">
    <field type="BigIntegerField" name="number">100809206</field>
    <field type="CharField" name="id">11700632</field>
    <field name="test123">
        <object pk="1" model="employee">
            <field type="DateTimeField" name="updated_on">27 Nov, 2014, 17:18 hrs</field>
            <field type="CharField" name="EmployeeName">ABC</field>
        </object>
        <object pk="2" model="employee">
            <field type="DateTimeField" name="updated_on">28 Nov, 2014, 17:18 hrs</field>
            <field type="CharField" name="EmployeeName">XYZ</field>
        </object>
        <object pk="3" model="employee">
            <field type="DateTimeField" name="updated_on">28 Nov, 2014, 17:18 hrs</field>
            <field type="CharField" name="EmployeeName">XYZ</field>
        </object>
    </field>
</object>

我的代码

BufferedReader in = new BufferedReader(new InputStreamReader(httpsURLConnection.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();

while ((inputLine = in.readLine()) != null)
{
    response.append(inputLine);
}
in.close();

if(response != null && !"".contains(response))
{
    SAXBuilder saxBuilder = new SAXBuilder();
    Document doc = saxBuilder.build(new StringReader(response.toString()));
    Element rootEle = doc.getRootElement();
    List childList = rootEle.getChildren();
    System.out.println(childList.toString());
    for(i=0;i<childList.size();i++)
    {
        Element shipment= (Element) childList.get(i);
        if(shipment != null)
        {
            List dataList  = shipment.getChildren();
            if(dataList != null && dataList.size() > 0)
            {
                List dataList  = shipment.getChildren();
                if(dataList != null && dataList.size() > 0)
                {
                    XMLOutputter xmlOutput = new XMLOutputter();
                    String shipmentXml = xmlOutput.outputString(shipment);
                    InputSource source = new InputSource(new StringReader(shipmentXml));
                    org.w3c.dom.Document document = DocumentBuilderFactory.newInstance().newDocumentBuilder().parse(source);
                    XPath xpath = XPathFactory.newInstance().newXPath();

                    String number = (xpath.evaluate("/object/field[@name ='number']", document).trim());
                    String name = (xpath.evaluate("/object/field[@name ='id']", document).trim());
                }
            }
        }
    }
}

我能够获得姓名和身份证明

<field type="BigIntegerField" name="number">100809206</field>
<field type="CharField" name="id">11700632</field>

但无法获得以下字段usimg xpath ..

<field name="test123">
        <object pk="1" model="employee">
            <field type="DateTimeField" name="updated_on">27 Nov, 2014, 17:18 hrs</field>
            <field type="CharField" name="EmployeeName">ABC</field>
        </object>
        <object pk="2" model="employee">
            <field type="DateTimeField" name="updated_on">28 Nov, 2014, 17:18 hrs</field>
            <field type="CharField" name="EmployeeName">XYZ</field>
        </object>
 </field>

如何获得价值“2014年11月27日17:18”和ABC使用属性“updated_on和EmployeeName分别

这2个标签变化可以从2变为5或更多..我想在for循环中迭代它并把它放在一些bean ..所以想要基于for循环

的标签名称的值

所以..基本上我想知道<object pk="1" model="employee">中有多少<field name="test123">个标签可供使用，并希望使用字段<object>遍历for循环中的每个updated_on and EmployeeName标记并获取它们的值并放入java bean。

Answer 1

如何获得价值“2014年11月27日，17：18”和ABC分别使用属性“updated_on和EmployeeName”

获取field[@type = 'DateTimeField']的正确路径表达式是

/object/field/object/field[@name = 'updated_on']

并获得field[@type = 'CharField']

/object/field/object/field[@name = 'EmployeeName']

您没有说为什么您无法检索这些节点，但我怀疑以下内容：您很可能已尝试使用类似

的表达式找到它们

/object/field[@name ='updated_on']

只有在XML结构如下时才有效：

<object>
  <field name="updated_on"/>
</object>

事实上，结构是

<object>
    <field>
        <object>
            <field name="updated_on"/>
        </object>
    </field>
</object>

只能使用//：

在树中的任何位置查找元素

//object/field[@name ='updated_on']

java中的Xml解析问题

1 个答案: