遍历java中的XML节点的问题

时间:2015-11-29 04:55:25

标签: java xml xml-parsing

我有一个在java中迭代xml的问题。我有一个根节点作为元素,在元素标签里面有两个子节点,但我得到节点长度为1.任何人都可以指导我如何纠正它。我在下面提到了我的代码。

import java.io.StringReader;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;

import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.CharacterData;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;


public class Test {




        public static void main(String arg[]) throws Exception{


             String xmlRecords = "<data><employee><name>A</name><title>Manager</title><name>B</name><title>Manager</title></employee></data>";

            DocumentBuilder db = DocumentBuilderFactory.newInstance().newDocumentBuilder();
            InputSource is = new InputSource();
            is.setCharacterStream(new StringReader(xmlRecords));

            Document doc = db.parse(is);

            NodeList nodes = doc.getElementsByTagName("employee");

            for (int i = 0; i < nodes.getLength(); i++) {
              Element element = (Element) nodes.item(i);

              NodeList name = element.getElementsByTagName("name");
              Element line = (Element) name.item(i);
              System.out.println("Name: " + getCharacterDataFromElement(line));

              NodeList title = element.getElementsByTagName("title");
              line = (Element) title.item(i);
              System.out.println("Title: " + getCharacterDataFromElement(line));
            }

          }

          public static String getCharacterDataFromElement(Element e) {
            Node child = e.getFirstChild();
            if (child instanceof CharacterData) {
              CharacterData cd = (CharacterData) child;
              return cd.getData();
            }
            return "";
          }

}

结果:

Name: A
Title: Manager

预期输出:

  Name: A
    Title: Manager
    Name: B
    Title: Manager

2 个答案:

答案 0 :(得分:2)

您的XML

<data>
   <employee>
      <name>A</name>
      <title>Manager</title>
      <name>B</name>
      <title>Manager</title>
   </employee>
</data>

我建议您尝试使用

<data>
   <employee>
      <name>A</name>
      <title>Manager</title>
   </employee>
   <employee>
      <name>B</name>
      <title>Manager</title>
   </employee>
</data>

否则(正确)只有1个员工节点,您打印名称和标题

答案 1 :(得分:0)

一些事情:只有一个151 - 160节点,所以你的循环迭代一次。考虑向String添加第二个节点:

<employee>

其次,对于String xmlRecords = "<data><employee><name>A</name><title>Manager</title></employee>" + "<employee><name>B</name><title>Manager</title></employee></data>"; <name>,不要在这些内部节点上进行迭代,因为每个员工中只有一个。因此,请使用零而不是<title>。这当然取决于上面的父节点更改。

i

按上述方法产生您想要的结果:

NodeList name = element.getElementsByTagName("name");
Element line = (Element) name.item(0);

NodeList title = element.getElementsByTagName("title");
line = (Element) title.item(0);