Question

我有一个包含字符串的数组：

["First Name", "Last Name", "Location", "Description"]

我需要将Array转换为Hash，如下所示：

{"A" => "First Name", "B" => "Last Name", "C" => "Location", "D" => "Description"}

此外，也是这样：

{"First Name" => "A", "Last Name" => "B", "Location" => "C", "Description" => "D"}

有任何想法如何处理这个最佳方式？

Answer 1

您可以按照以下方式实施

 def string_array_to_hash(a=[],keys=false)
    headers = ("A".."Z").to_a
    Hash[keys ? a.zip(headers.take(a.count)) : headers.take(a.count).zip(a)]
 end

然后得到你的初始输出就是

 a = ["First Name", "Last Name", "Location", "Description"]
 string_array_to_hash a 
 #=> {"A"=>"First Name", "B"=>"Last Name", "C"=>"Location", "D"=>"Description"}

第二个输出是

 a = ["First Name", "Last Name", "Location", "Description"]
 string_array_to_hash a, true 
 #=> {"First Name"=>"A", "Last Name"=>"B", "Location"=>"C", "Description"=>"D"}

注意：只要a小于27个对象，这将有效，否则您必须指定不同的所需输出。这是因为a）字母表只有26个字母b）哈希对象只能有唯一的键。

Answer 2

你可以这样做：

arr = ["First Name", "Last Name", "Location", "Description"]

letter = Enumerator.new do |y|
  l = ('A'.ord-1).chr
  loop do
    y.yield l=l.next
  end
end
  #=> #<Enumerator: #<Enumerator::Generator:0x007f9a00878fd8>:each> 

h = arr.each_with_object({}) { |s,h| h[letter.next] = s }
  #=> {"A"=>"First Name", "B"=>"Last Name", "C"=>"Location", "D"=>"Description"} 

h.invert
  #=> {"First Name"=>"A", "Last Name"=>"B", "Location"=>"C", "Description"=>"D"}

或

letter = ('A'.ord-1).chr
  #=> "@" 
h = arr.each_with_object({}) { |s,h| h[letter = letter.next] = s }
  #=> {"A"=>"First Name", "B"=>"Last Name", "C"=>"Location", "D"=>"Description"}

使用枚举器letter时，我们有

27.times { puts letter.next }
  #=> "A"
  #   "B"
  #   ...
  #   "Z"
  #   "AA"

Answer 3

如果您没有具体说明密钥名称，那么您可以试试这个

 list = ["First Name", "Last Name", "Location", "Description"] 
 Hash[list.map.with_index{|*x|x}].invert

输出

 {0=>"First Name", 1=>"Last Name", 2=>"Location", 3=>"Description"}

类似的解决方案是here。

Answer 4

或..你也可以试试这个：）

letter = 'A'
arr = ["First Name", "Last Name", "Location", "Description"]
hash = {}
arr.each { |i|
hash[i] = letter
letter = letter.next
}

// => {"First Name"=>"A", "Last Name"=>"B", "Location"=>"C", "Description"=>"D"}

或

letter = 'A'
arr = ["First Name", "Last Name", "Location", "Description"]
hash = {}
arr.each { |i|
hash[letter] = i
letter = letter.next
}

// => {"A"=>"First Name", "B"=>"Last Name", "C"=>"Location", "D"=>"Description"}

在Ruby中将字符串数组转换为哈希值

4 个答案: